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Answer:
angular frequency of the table must be same as the frequency of the projection of the gum on the wall
Explanation:
Since we know that the projection on the wall is the vertical component of the position of the gum on the rotating table
So here we will say
so the angle made by the radius vector depends on the angular frequency of the disc by which it is rotating
So we can say
so here we can say
so here we can say that
angular frequency of the table must be same as the frequency of the projection of the gum on the wall
The image formed from the lens is real, inverted and enlarged
Explanation:
The magnification of a lens is given by:
(1)
where:
y' is the size of the image
y is the size of the object
q is the distance of the image from the lens
p is the distance of the object from the lens
For this lens, the magnification is
m = -1.6
We notice the following:
- The magnification is negative
- The magnification is larger than 1
Looking at eq.(1), we can therefore make the following conclusions:
- SInce and
, it follows that
, so the image is larger than the object
- Since and
, it follows that
(since y > 0 for convention): this means that the image is inverted
- Since and
, it follows that
(since p > 0 for convention): this means that the image is real
Learn more about lenses and mirrors here:
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