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A 34kg crate resting on a horizontal surface is pushed as shown. If the coefficient of static friction s between the surfaces is

ioda

Answer:

D (not so sure, look in the explanation and judge yourself)

Explanation:

Assume that the acceleration due to gravity is 9.81 m/s^2 downwards

Minimum force required = 0.25 x 34 x 9.81

= 83.385 N

So technically the force need to be greater than 83.385 so the answer should be d, not really sure if it should be b though really depends on the acceleration due to gravity.

7 0

3 years ago

along region C on this speed vs. time, an object is __. a. not moving b.increasing its speed c. decreasing its speed

Zigmanuir [339]

<span>the answer is a. not moving</span>

4 0

3 years ago

Instead of clear-cutting land and moving on, a local lumber business decides to start farming trees: cutting some of the trees a

Nuetrik [128]

I think your answer would be C. because they are replacing the trees they are cutting down.

5 0

3 years ago

Read 2 more answers

A car accelerates in the +x direction from rest with a constant acceleration of a1 = 1.76 m/s2 for t1 = 20 s. At that point the

alex41 [277]

Answer:

(a) $v_1 = a_1t_1 = 1.76 t_1$

(b) It won't hit

(c) 110 m

Explanation:

(a) the car velocity is the initial velocity (at rest so 0) plus product of acceleration and time t1

$v_1 = v_0 + a_1t_1 = 0 +1.76t_1 = 1.76t_1$

(b) The velocity of the car before the driver begins braking is

$v_1 = 1.76*20 = 35.2m/s$

The driver brakes hard and come to rest for t2 = 5s. This means the deceleration of the driver during braking process is

$a_2 = \frac{\Delta v_2}{\Delta t_2} = \frac{v_2 - v_1}{t_2} = \frac{0 - 35.2}{5} = -7.04 m/s^2$

We can use the following equation of motion to calculate how far the car has travel since braking to stop

$s_2 = v_1t_2 + a_2t_2^2/2$

$s_2 = 35.2*5 - 7.04*5^2/2 = 88 m$

Also the distance from start to where the driver starts braking is

$s_1 = a_1t_1^2/2 = 1.76*20^2/2 = 352$

So the total distance from rest to stop is 352 + 88 = 440 m < 550 m so the car won't hit the limb

(c) The distance from the limb to where the car stops is 550 - 440 = 110 m

8 0

3 years ago

A car travels 10.0 m/s. What is its velocity in km/h?

Vitek1552 [10]

Since 1m/s=3.6 km/h, we can conclude that 10.0m/s = 36 km/h

5 0

3 years ago

Please help me with this speed thigh Help help