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sukhopar [10]
3 years ago
5

7. Peter found an amazing fact in an amusement park when he tried to ride the Magic Mountain Superman. Powerful magnets accelera

te a car and its riders from zero to 45 m/s in 7 seconds. Suppose the mass of the car and riders is 5,600 kg. What is the average net force exerted on the car and riders by the magnets?
Physics
1 answer:
GuDViN [60]3 years ago
7 0

The average net force exerted is 36000 N.

<u>Explanation</u>:

According to Newton's 2nd law of motion,

The net force acting upon the object is the product of mass and acceleration of an object.

                                Force = ma

where m represents the mass,

          a represents the acceleration.

                  Acceleration = (change in speed) / (change in time)

                   Acceleration = (45 m/s) / (7 sec) = (45 / 7) m/s²

                              Force = (5,600 kg) x (45 /7  m/s²)

                              Force = (800 x 45) Newtons

                              Force = 36000 Newtons.

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A Porsche challenges a Honda to a 400 m race. Because the Porsche’s acceleration is 3.50 m/s2 is larger than the Honda’s 3.00 m/
Talja [164]

Answer:

There are a couple of ways to do this.

(i) Set up the two kinematics equations:

Honda: s = ½at² = ½ * 3m/s² * t² = 1.5m/s² * t²

Porsche: S = ½ * 3.5m/s² * (t - 1s)² = 1.75m/s² * (t - 1s)²

When does s = S ? Dropping units for ease,

1.5t² = 1.75(t-1)²

which is quadratic and has solutions at t = 0.5 s → which is no good, since it would leave the porsche with -0.5 s, which isn't possible, and

t = 13.5 s

When they've gone the same distance, they've gone

d = 1.5m/s² * (13.5s)² = 273 meters

The Porsche wins easily. ◄

Want to make it interesting? Give the Honda 1¼ seconds.

Then t = 16.85 s

and x = 1.5m/s² * (16.85s)² = 426 m

and the Honda squeaks out a victory.

You could also just find the time it takes each to go 400 m:

Honda: t = √(2s/a) = √(800m / 3.0m/s²) = 16.3 s

Porsche: T = √(800m / 3.5m/s²) = 15.1 s

Since the Porsche only gives up 1 s at the beginning, it wins by 0.2 s.

Explanation:

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3 years ago
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Irina-Kira [14]
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3 0
3 years ago
What Is the Formula for Velocity vector<br> i wll brain u if ur fast at it
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3 years ago
Concave lenses have _ focal lengths and always form _ images
zhannawk [14.2K]

The correct answer of this question is : Negative focal length and virtual images.

EXPLANATION:

The concave lens is that transparent spherically refracting surface which is diverging in nature. It is so because it is bulged at the edges and thinner in the centre.

The focal length of the concave lens is always taken negative.

As the lens is diverging in nature, it always forms virtual,erect and diminished image. It means the image formed by concave lens has less size as compared to object.

Hence, the correct answer of this question is that concave lenses have negative focal length and always form virtual images.

4 0
3 years ago
A pair of eyeglass frames are made of an epoxy plastic (coefficient of linear expansion = 122 ✕ 10-6 °C-1). At room temperature
il63 [147K]

Answer:

The new temperature is  T_1 =  60.78^oC

Explanation:

From the question we are told that

   The coefficient of linear expansion is  \sigma  =  122 *10^{-6} \ ^oC^{-1}

    The temperature is  T  =  20.0 ^oC

    The radius of the frames is r =  2.00 \  cm  = 0.02 \ m

    The new radius is  r_2 =  2.01 \ cm =  0.021 \ m

The change in radius is mathematically represented as

       \Delta r =  r_1 -r

substituting values

       \Delta r =  2.01 - 2.00

       \Delta r =  0.01 \ m

The increase in radius can also be mathematically represented as

     \Delta  r  =  r * \sigma (T_1 -T)

Where T_1 is the the new temperature , making it the subject we have

      T_1 =  \frac{\Delta  r}{r * \sigma  } + T

substituting value  

     T_1 =  \frac{0.01}{2.01 *122*10^{-6}  } + 20

    T_1 =  60.78^oC

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4 years ago
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