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4 years ago

What is the scentific notation of 803,000

Mathematics

2 answers:

Vlad1618 [11]4 years ago

7 0

8x10^.6 im pretty sure

Orlov [11]4 years ago

6 0

8.03 times 10^5 or
8.03e+05

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A teacher has 27 students in her class. She asks the students to form as many groups of 4 as possible. How many students will no

Talja [164]

3 people will be in each group because 3*9=27

8 0

3 years ago

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47, 40, 36, 40, 42, 45, 40, 32. Are the mean, median and mode of the above data the same? If not

horrorfan [7]

Answer:

mean: 40.25

median: 40

mode: 40

Step-by-step explanation:

No.

If 42 is removed all values will be equal to 40.

4 0

3 years ago

Chords and intersect in circle O as shown in the diagram. Two of the angle measurements are marked. What is mCED?

jenyasd209 [6]

we know that

The measure of the interior angle is the half sum of the arcs comprising it and its opposite

m∠CED= $\frac{1}{2} *(arc\ AB+arc\ CD)$

see the attached figure with letters to better understand the problem

$arc\ AB=82$ ° ------> by central angle

$arc\ CD=48$ ° ------> by central angle

Substitute the values in the formula above

m∠CED= $\frac{1}{2} *(82+48)$

m∠CED= $\frac{1}{2} *130$

m∠CED= $65$ °

therefore

<u>the answer is</u>

m∠CED= $65$ °

8 0

3 years ago

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What is the following profuct?<br><br> ( sqrt 14 - sqrt 3) ( sqrt 12 + sqrt 7)

GalinKa [24]

Using the distributive law:-

this = sqrt 14 sqrt 12 + sqrt 14 sqrt 7 - sqrt 3 sqrt 12 - sqrt 3 sqrt 7

= sqrt1 68 + sqrt 91 - sqrt 36 - sqrt 21

= sqrt 168 + sqrt 91 - sqrt21 - 6

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4 years ago

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Find r(t) if r'(t) = 5t4i + 6t5j + t k and r(1) = i + j.

Vladimir [108]

$\mathbf r(t)=\displaystyle\int(5t^4\,\mathbf i+6t^5\,\mathbf j+t\,\mathbf k)\,\mathrm dt$
$\mathbf r(t)=(t^5+C_1)\,\mathbf i+(t^6+C_2)\,\mathbf j+\left(\dfrac12t^2+C_3\right)\,\mathbf k$

Given $\mathbf r(1)=\mathbf i+\mathbf j$ , we have

$\begin{cases}1^5+C_1=1\\\\1^6+C_2=1\\\\\dfrac121^2+C_3=0\end{cases}\implies C_1=0,C_2=0,C_3=-\dfrac12$

so that the particular solution is

$\mathbf r(t)=t^5\,\mathbf i+t^6\,\mathbf j+\dfrac12(t^2-1)\,\mathbf k$

8 0

3 years ago