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3 years ago

I need help pls!!!!!!!!

Mathematics

1 answer:

KATRIN_1 [288]3 years ago

4 0

The y-intercept is -7

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Laura wants to place one flowerpot 3/4 every meters along the path from the gate to the main entrance of her home. The path is 1

Alex17521 [72]

Answer:

Step-by-step explanation:

3/4 = 0.75

12/0.75=16

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2 years ago

test worth 70 points; test score of 90% write a proportion to find how many points a student needs to earn on the test to get th

GaryK [48]

70/70 = 100%
35/70 =50%
63/70=90%

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3 years ago

Sadie has $1 worth of nickels and dimes. She has twice as many nickels as dimes. Write a system of equations that could be used

zepelin [54]

N + 2d =1
This is the system of equations because it is 2 times more than nickels

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3 years ago

31. Last month, Sharon's Deli charged the Business Club $231

finlep [7]

Answer:hello the answer is C. 7$

Step-by-step explanation:

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3 years ago

Not all visitors to a certain company's website are customers. In fact, the website administrator estimates that about 5% of all

Gnom [1K]

Answer:

0.0135 = 1.35% probability that, in a random sample of 4 visitors to the website, exactly 2 actually are looking for the website.

Step-by-step explanation:

For each visitor of the website, there are only two possible outcomes. Either they are looking for the website, or they are not. The probability of a customer being looking for the website is independent of other customers. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

5% of all visitors to the website are looking for other websites.

So 100 - 5 = 95% are looking for the website, which means that $p = 0.95$

Find the probability that, in a random sample of 4 visitors to the website, exactly 2 actually are looking for the website.

This is P(X = 2) when n = 4. So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = x) = C_{4,2}.(0.95)^{2}.(0.05)^{2} = 0.0135$

0.0135 = 1.35% probability that, in a random sample of 4 visitors to the website, exactly 2 actually are looking for the website.

5 0

2 years ago