Beaker would be most appropriate for measuring the approximate volume of a liquid.
... find length
(way 1) determine acceleration using force
only force act on skier is mg vertically. spilt vector we get force along the incline = mgsin(10) and f= ma so
ma = mgsin(10) or a = gsin(10)
a (along the incline)= gsin(10) = 10sin(10) = 1.74
v^2 = u^2 + 2as
15^2 = 3^2 + 2(1.74)s
s = 62.06 m
(way 2) using conservation of energy
energy (KE+PE) on top = energy at bottom
0.5m3^2 + mgh = 0.5m15^2 +0
h (height of incline) = (112.5 - 4.5)/10 = 19.8 m
length of incline = h/sin(10) = 62.2 m ; trigonometry
... find time
s = (u+v)t/2
t = 2s/(u+v) = 2(62.2)/(3+15) = 6.91 s
Answer:
because there is external pressure is less in the height.
hope it helps.
<h3>
Answer:</h3>
189.07 kPa
<h3>
Explanation:</h3>
Concept tested: Boyle's law
<u>We are given;</u>
- Initial volume of the syringe, V1 is 16 cm³
- Initial pressure of the syringe, P1 is 1.03 atm
- New volume of the syringe, V2 is 8.83 cm³
We are required to calculate the new pressure of the syringe;
- We are going to use the concept on Boyle's law of gases.
- According to the Boyle's law, for a fixed mass of a gas, the pressure is inversely proportional to its volume at constant temperature.
- At varying pressure and volume, k(constant) = PV and P1V1=P2V2
Therefore, to get the new pressure, P2, we rearrange the formula;
P2 = P1V1 ÷ V2
= ( 16 cm³ × 1.03 atm) ÷ 8.83 cm³
= 1.866 atm.
- Thus, the new pressure is 1.866 atm
- But, we need to convert pressure to Kpa
- Conversion factor is 101.325 kPa/atm
Thus;
Pressure = 1.866 atm × 101.325 kPa/atm
= 189.07 kPa
Hence, the new pressure of the air in the syringe is 189.07 kPa
Answer:
It will require a force of 1/5, answer A.
Explanation:
In the attached image we can see an example of an array of pulleys that will lift a 100 kg-f load.
If we analyze pulleys A,B, and C as in the image we can check a force in the cable of 20kg-f.
In the pulley D we have three forces of 20 kg-f each and those forces plus the forces in the pulley B, sum a total of 100 kg-f (60+40). This matches the mechanical advantage (100/5) = 20 kg-f