A space vehicle is coasting at a constant velocity of 22.3 m/s in the y direction relative to a space station. The pilot of the
vehicle fires a RCS (reaction control system) thruster, which causes it to accelerate at 0.277 m/s^2 in the x direction. After 46.6 s, the pilot shuts off the RCS thruster. After the RCS thruster is turned off, find:
a. The magnitude.
b. The direction of the vehicle's velocity relative to the space station. Express the direction as an angle (in degrees) measured from the y direction.
a. The magnitude.
b. The direction of the vehicle's velocity relative to the space station. Express the direction as an angle (in degrees) measured from the y direction.
1 answer:
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Answer:
It will require a force of 1/5, answer A.
Explanation:
In the attached image we can see an example of an array of pulleys that will lift a 100 kg-f load.
If we analyze pulleys A,B, and C as in the image we can check a force in the cable of 20kg-f.
In the pulley D we have three forces of 20 kg-f each and those forces plus the forces in the pulley B, sum a total of 100 kg-f (60+40). This matches the mechanical advantage (100/5) = 20 kg-f
