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zaharov [31]
3 years ago
12

A person is just as likely to become dehydrated in the cold as in the heat. Please select the best answer from the choices provi

ded. T F
Physics
2 answers:
alexdok [17]3 years ago
8 0
The answer would be A) TRUE because we as humans can be dehydrated easily just by working out in sun or working out in the cold winter, that's how our body burns fat and calories, but it also burns our eyes since sweat has salt in it, and dehydrated means to run out of water for us, like not enough water, but yes to the answer its T.
777dan777 [17]3 years ago
4 0

A person is not only dehydrated during summer time but also in cold dry weather.

During cold dry weather we loss more fluids due to loss of water in respiratory parts.At that time our blood vessels constrict which makes it difficult for blood to flow freely to extremities.


During winter time one feels less thirsty.It is so because sweat evaporates very quickly in cold weather which decreases our thirst response. At that time more urine is also produced.


Hence the statement given in the question is true(T).


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Unpolarized light passes through a vertical polarizing filter, emerging with an intensity I0. The light then passes through a ho
antiseptic1488 [7]

To solve this problem it is necessary to apply the concepts related to Malus' law. Malus' law indicates that the intensity of a linearly polarized ray of light that passes through a perfect analyzer with a vertical optical axis is equivalent to:

I = I_0 cos^2(\theta)

I_0 = Indicates the intensity of the light before passing through the Polarizer,

I = The resulting intensity, and

\theta = Indicates the angle between the axis of the analyzer and the polarization axis of the incident light.

There is 3 polarizer, then

For the exit of the first polarizer we have that the intensity is,

I_2 = I_0cos^2(45)

For the third polarizer then we have,

I_3 = I_2 cos^{2}(45)

Replacing with the first equation,

I_3 =  I_0cos^2(45)cos^{2}(45)

I_3 = I_0 (\frac{1}{2})(\frac{1}{2})

I_3 = I_0 \frac{1}{4}

Therefore the transmitted intensity now is \frac{1}{4} of the initial intensity.

5 0
4 years ago
Does a star's apparent brightness depend only on its distance from earth?
Arisa [49]
I dont think so. It also probably matters what type of str it is
4 0
3 years ago
Read 2 more answers
A student lifts a box of books 2 meters with a force of 45 N. He then carries the box 10 meters to the living room. What is the
Alisiya [41]

Answer:

90J

Explanation:

The only time work is being done is when he lifts the box off the ground. Therefore, using the work formula, 2 x 45, you get 90J. Hope this helps someone.

5 0
3 years ago
Two forces act on a 6.00-kg object. One of the forces is 10.0 N. If the object accelerates at 2.00 m/s2
liubo4ka [24]

Given :

Two forces act on a 6.00-kg object. One of the forces is 10.0 N.

Acceleration of object 2 m/s².

To Find :

The greatest possible magnitude of the other force.\

Solution :

Let, other force is f.

So, net force, F = 10 + f.

Now, acceleration is given by :

a=\dfrac{F}{mass}\\\\a= \dfrac{10+f}{6}\\\\\dfrac{10+f}{6}=2\\\\f = 12 - 10\\\\f = 2 \ N

Therefore, the greatest possible magnitude of the other force is 2 N.

Hence, this is the required solution.

7 0
3 years ago
A bubble, located 0.200 m beneath the surface in a glass of beer, rises to the top. The air pressure at the top is 1.01 ???? 10
SIZIF [17.4K]

Answer:

the ratio of the bubble’s volume at the top to its volume at the bottom is 1.019

Explanation:

given information

h = 0.2 m

P_{0} = 1.01  x 10^{5} Pa

P_{1} V_{1} = P_{2} V_{2}

\frac{V_{2} }{V_{1}} = \frac{P_{1} }{P_{2}}

P_{1}  = P_{0}  + ρgh, ρ = 1000 kg/m^{3}

P_{1}  = 1.01 x 10^{5} Pa + (1000 x 9.8 x 0.2) = 1,0296 x 10^{5} Pa

P_{2}  = P_{0}  = 10^{5} Pa

thus,

\frac{V_{2} }{V_{1}} = 1,0296 x [tex]10^{5}/10^{5} = 1.019

8 0
3 years ago
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