a 5.5 kg box is pushed across the lunch table.the net force applied to the box is 9.7 N.what is the acceleration of the box?
1 answer:
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Answer:
q = 3.6 10⁵ C
Explanation:
To solve this exercise, let's use one of the consequences of Gauss's law, that all the charge on a body can be considered at its center, therefore we calculate the electric field on the surface of a sphere with the radius of the Earth
r = 6 , 37 106 m
E = k q / r²
q = E r² / k
q =
q = 4.5 10⁵ C
Now let's calculate the charge on the planet with E = 222 N / c and radius
r = 0.6 r_ Earth
r = 0.6 6.37 10⁶ = 3.822 10⁶ m
E = k q / r²
q = E r² / k
q =
q = 3.6 10⁵ C
Answer:
1. a
b
c
2.
Explanation:
a). The work done by the tension is:
b). The work done potential of gravity
c). The work done by the normal force
2. The increase in thermal energy is: