During the period of 2 hours, the yeast ate the sugar, and generated Carbon-Dioxide gas and alcohol. This is the process that causes bread-dough to rise, and eventually produces stuff that can be distilled to concentrate the alcohol and make wine or whiskey.
-- If Daniel tied the neck of the balloon, so that nothing could get in r out during the 2 hours, then the mass of the balloon and everything inside it didn't change. The balloon may have inflated slightly ... due to the creation of gas inside that wasn't there before ... just like bread dough. But no mass was created or destroyed inside or outside of the balloon, and none got in or out.
-- If Daniel left the neck of the balloon open, then the mass of the balloon and its contents decreased slightly during the 2 hours. The yeast took carbon and oxygen from the sugar, and used them to make Carbon Dioxide gas. Then the gas flew out through the neck of the balloon to Freedom.
48J
Explanation:
Given parameters:
Weight of the book = 16N
Height of the shelf = 3m
Unknown:
Work done to raise the book = ?
Solution:
Work done is defined as the product of force and distance. The force here is the weight of the book which signifies that it was carried in the vicinity of gravitational force.
Work done = Force x distance = weight x distance
Weight is a type of force;
Input the parameters;
Work done = 16 x 3 = 48J
The unit of workdone is in Joules
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Work done brainly.com/question/9100769
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Answer and Explanation:
with reference to Einstein's theory of special relativity, the speed of an electromagnetic radiation, here, laser will not change in any inertial frame or remains same irrespective of any change in inertial frame.
Therefore, the speed of light measured in both the cases, i.e., in astronaut's reference frame and spaceship's reference frame will be equal to the speed of light in vacuum, i.e.,
.
The laser gun's speed in astronaut's reference frame is the same as the speed of the spaceship as it mounted on it, i.e., the speed of the laser gun is 200 million m/s.
The laser gun's speed measured in spaceship's reference frame will be zero, as it is mounted on the spaceship and is stationary in the spaceship's reference frame.
My Anonymuos friend, I could not agree more with your statement.
Truer words have rarely if ever been expressed.