A 7800 W lift took 10 seconds to move a 5000 N weight. How far did the lift move this weight?
1 answer:
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The molarity is 0.018M and the percentage is 8.46%.
Net ionic reaction is
of
reacts with
of
to form
of
and
of
Find molarity of
Molarity = moles of Volume of
)
Moles of = grams of
molar mass of
Molarity of moles of
/ Volume of
(L)
Find molarity of (II)
Molarity of molarity of
volume of
volume of
(II)
Find moles of
Moles of molarity of
(II)
volume of
(II)
Find mass of Fe(II)
Mass of moles of
)
molar mass of
Find in unknown sample
- Molarity is the concentration of a solution expressed as the number of moles of solute dissolved in each liter of solution.
- concentration is the amount of a substance per defined space. Concentration usually is expressed in terms of mass per unit volume.
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Answer:
The ranking of the net force acting on different satellite from largest to smallest is
Explanation:
In order to get a good understanding of this solution we need to understand that the main concepts used to solve this problem are centripetal force and velocity of satellite.
Initially, use the expression of the velocity of satellite and find out its dependence on the radius of orbit. Use the dependency in the centripetal force expression.
Finally, we find out the velocity of the six satellites and use that expression to find out the force experienced by the satellite. Find out the force in terms of mass (m) and radius of orbit (L) and at last compare the values of force experienced by six satellites.
Fundamentals
The centripetal force is necessary for the satellite to remain in an orbit. The centripetal force is the force that is directed towards the center of the curvature of the curved path. When a body moves in a circular path then the centripetal force acts on the body.
The expression of the centripetal force experienced by the satellite is given as follows:
Here, m is the mass of satellite, v is the velocity, and L is the radius of orbit.
The velocity of the satellite with which the satellite is orbiting in circular path is given as follows:
Here, T is the time taken by the satellite.
The velocity of the satellite with which the satellite is orbiting in circular path is given as follows;
Since, all the satellites complete the circular orbit in the same amount of time. The factor of is not affected the velocity value for the six satellites. Therefore, we can write the expression of v given as follows:
Substitute in the force expression
as follows:
Since, all the satellites complete the circular orbit in the same amount of time. The factor of not affect the force value for six satellites.Therefore, we can write the expression of
given as follows:
Here, k refers to constant value and equal to
Substitute 200 kg for and 5000 m for LA in the expression
The force acting on satellite B from their rocket is given as follows:
Substitute 400 kg for and 2500 m for in the expression
The force acting on satellite C from their rocket is given as follows:
Substitute 100 kg for and 2500 m for in the above expression
The force acting on satellite D from their rocket is given as follows:
Substitute 100 kg for and 10000 m for
in the expression
The force acting on satellite E from their rocket is given as follows:
Substitute 800 kg for and 5000 m for
in the expression
The force acting on satellite F from their rocket is given as follows:
Substitute 300 kg for and 7500 m for
in the expression
The value of forces obtained for the six-different satellite are as follows.
The ranking of the net force acting on different satellite from largest to smallest is