Answer:
1) 64.2 mi/h
2) 3.31 seconds
3) 47.5 m
4) 5.26 seconds
Explanation:
t = Time taken = 2.5 s
u = Initial velocity = 0 m/s
v = Final velocity = 21.7 m/s
s = Displacement
a = Acceleration
1) Top speed = 28.7 m/s
1 mile = 1609.344 m

1 hour = 60×60 seconds


Top speed of the cheetah is 64.2 mi/h
Equation of motion

Acceleration of the cheetah is 8.68 m/s²
2)

It takes a cheetah 3.31 seconds to reach its top speed.
3)

It travels 47.5 m in that time
4) When s = 120 m

The time it takes the cheetah to reach a rabbit is 120 m is 5.26 seconds
100 J
Please mark me brainliest it would be greatly appreciated haha
Answer:
when work is done on the system or heat comes into the system
2 is c
3 is a
4 is b
5 is c
To solve this problem we will apply the geometric concepts of displacement according to the description given. Taking into account that there is an initial displacement towards the North and then towards the west, therefore the speed would be:


Travel north 2mph and west to 1mph, then,


The route is done exactly the same to the south and east, so make this route twice, from the definition of speed we have to




Therefore the total travel time for the man is 1.15hour.