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SCORPION-xisa [38]
2 years ago
10

A 7800 W lift took 10 seconds to move a 5000 N weight. How far did the lift move this weight?

Physics
1 answer:
Eduardwww [97]2 years ago
7 0

Answer:

Both are moving at 30 km/h, so their speed is the same. ... enough fuel for the trip/how long it will take. 4 Weight is a force, and so is a vector. ... c At 10 seconds David's displacement is.

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The distance between two charged objects is doubled. What happens to the electrostatic force between the two?a)It will double.b)
zzz [600]

Answer:

d) It will be cut to a fourth of the original force.

Explanation:

The magnitude of the electrostatic force between the charged objects is

F=k\frac{q_1 q_2}{r^2}

where

k is the Coulomb's constant

q1 and q2 are the charges of the two objects

r is the separation between the two objects

In this problem, the initial distance is doubled, so

r' = 2r

Therefore, the new electrostatic force will be

F=k\frac{q_1 q_2}{(r')^2}=k\frac{q_1 q_2}{(2r)^2}=\frac{1}{4}(k\frac{q_1 q_2}{r^2})=\frac{1}{4}F

So, the force will be cut to 1/4 of the original value.

5 0
3 years ago
What is the length of a string with a mass of 2.5 kg, with a
natulia [17]
B 0.4 m should be correct if not it is A
4 0
3 years ago
Water has a mass per mole of 18.0 g/mol, and each water molecule (H20) has 10 electrons. (a) How many electrons are there in one
Allushta [10]

Answer:

total number of electron in 1 litter is 3.34 × 10^{26} electron

Explanation:

given data

mass per mole = 18 g/mol

no of electron = 10

to find out

how many electron in 1 liter of water

solution

we know molecules per gram mole is 6.02 ×10^{23} molecules

no of moles is 1

so

total number of electron in water is = no of electron ×molecules per gram mole × no of moles

total number of electron in water is = 10 × 6.02 ×10^{23} × 1

total number of electron in water is = 6.02×10^{24} electron

and

we know

mass = density × volume    ..........1

here we know density of water is 1000 kg/m

and volume = 1 litter = 1 × 10^{-3} m³

mass of 1 litter = 1000 × 1 × 10^{-3}

mass = 1000 g

so

total number of electron in 1 litter =  mass of 1 litter × \frac{molecules per gram mole}{mass per mole}

total number of electron in 1 litter =  1000 × \frac{6.02*10{24}}{18}

total number of electron in 1 litter is 3.34 × 10^{26} electron

8 0
3 years ago
Suppose that, from measurements in a microscope, you determine that a certain bacterium covers an area of 1.50 μm2. Convert this
Paladinen [302]
1 m = 1 000 000 ym

converted other way we can say that:

1 ym = 10^{-6} m

Now, since we have ym^2 which is ym*ym which means:
1 ym^2 = (10^{-6}) ^2  =  10^{-12} m

we have 1,5 ym^2 which means that answer is:
1.5* 10^{-12} m
8 0
3 years ago
Consider a perfectly reflecting mirror oriented so that solar radiation of intensity i is incident upon, and perpendicular to, t
podryga [215]
The answer is Frad<span> = 2IA/c.</span>
4 0
3 years ago
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