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3 years ago

Name two objects that have a low density.

Physics

1 answer:

Vinil7 [7]3 years ago

4 0

-- a party balloon that's full of helium and resting on the ceiling

-- a piece of styrofoam

-- a cloud of smoke

-- a bag of hot air

-- a cirrus cloud in the sky

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Classify each of the following hydro carbons as alkane,alkene or alkyne

timofeeve [1]

Answer:

a.)alkene

b.)alkane

d.)alkana

about c..I think there is something wrong with the question

5 0

3 years ago

Two metal spheres of different sizes are charged such that the electric potential is the same at the surface of each. Sphere A h

vodka [1.7K]

Answer:

Explanation:

Given

Radius of A is twice of B i.e.

$R_A=2R_B$

Also Potential of both sphere is same

$V_A=V_B$

$V=\frac{kQ}{R}$

thus

$k\frac{Q_A}{R_A}=K\frac{Q_B}{R_B}$

$\frac{Q_A}{Q_B}=\frac{R_A}{R_B}$

$\frac{Q_A}{Q_B}=\frac{2}{1}=2$

$\frac{Q_B}{Q_A}=\frac{1}{2}$

(b)Ratio of $\frac{E_B}{E_A}$

Electric Field is given by $E=\frac{kQ}{R^2}$

thus $E_A=\frac{kQ_A}{R_A^2}$ ----1

$E_B=\frac{kQ_B}{R_B^2}$ ----2

Divide 2 by 1

$\frac{E_B}{E_A}=\frac{Q_B}{R_B^2}\times \frac{R_A^2}{Q_A}$

$\frac{E_B}{E_A}=\frac{1}{2}\times 4=2$

8 0

4 years ago

A good-quality measuring tape can be off by 0.42 cm over a distance of 28 m. What is its percent uncertainty? (Express your answ

Alecsey [184]

Answer:

0.015%

Explanation:

Data provided in the question:

Length by which the measuring tape can be off, δL = 0.42 cm

Total measured length for which Error of δL is observed, L = 28 m

Now,

we know,

1 m = 100 cm

Thus,

28 m = 28 × 100 = 2800 cm

Percent uncertainty = [δL ÷ L] × 100%

= [0.42 ÷ 2800] × 100%

= 0.015%

5 0

3 years ago

What is the net force on the side of the container The initial height of the water in a sealed container of diameter 100.0 cm is

Gala2k [10]

Answer:

26467.21 N

Explanation:

Initial height of water ( h1 ) = 5 m

diameter of container ( d1 )= 100 cm

pressure inside the container ( p1 )= 0.850 atm

Diameter of faucet ( d2 )= 1 inch

<u>Calculate the value of the net force on the side of container</u>

lets assume ; pressure outside the container ( p2 ) = 1 atm

Fnet = ( P1A1 + mg ) - ( P2A2 )

= [ ( 0.85 * 101325 ) ( π(1/2)^2 ) + mg ) - [ ( 101325 )( π )(0.0127)^2 ]

= [ 16902.2766 + pvg ] - [ 51.3161 ]

where ; pvg = pAhg = 1000 * π ( 1/2 )^2 * 5 * 9.8 = 9616.25

= [ 16902.2766 + 9616.25 ] - [ 51.3161 ] = 26467.21 N ( downwards )

5 0

3 years ago

What is the electric field strength 7.50 x 10E-1 meters from a 2.8 x 10 E-3 C charged object?

Nadusha1986 [10]

Answer:hi

Explanation:

5 0

3 years ago