Answer:
485520 m
Explanation:
= initial velocity of the projectile = 1360 m/s
= final velocity of the projectile = 
= 
= 544 m/s
a = acceleraton due to gravity on moon = - 1.6 m/s²
h = Altitude of the projectile
Using the kinematics equation
Inserting the values
h = 485520 m
Answer:
A. cause i just took the test
Explanation:
I think you should hold a stretch for 10-30 seconds
Answer:
The kinetic energy of the phone would increase. The gravitational potential energy of the phone would decrease.
Explanation:
The kinetic energy 
of an object is proportional to the square of the speed of that object. If air resistance is negligible, the phone would accelerate under gravitational pull and speed up. Hence, the kinetic energy of the phone would increase.
The gravitational field near the surface of the earth is approximately constant. Hence, the gravitational potential energy 
of the phone would be proportional to its height. As the phone approaches the ground, the height of the phone becomes lower and the gravitational potential energy of the phone would decrease.
Answer:
d. the actual motion is regular, but the speeds of particles are too large to observe the regular motion
Explanation:
The speeds of the particles are very large and comparatively the average free path is very small . Therefore time taken in covering the free path ( path between two consecutive collision with medium particles ) is very small . Hence the st line path covered by particles between two collision is less likely to be visible. Hence motion appears irregular or zig-zag.
