Ask question

Ask question

All categories

3 years ago

8

How do you label Time= energy • power

1 answer:

Lana71 [14]3 years ago

5 0

First of all, that equation is not correct, which may be the reason
that you're having trouble assigning units to the quantities.

Power is defined as [energy / time], so [Energy] = [ power x time ],
and
[Time] = [ energy / power ].

Unit-wise, these equations are correct just as they appear here,
with no proportionality constants or conversion factors, when ...

[ Power ] = watts
[ Energy ] = joules
[ Time ] = seconds .

You might be interested in

1. Determine the magnitude of two equal but opposite charges if they attract one another with a force of 0.7N when at distance o

adell [148]

Answer:

q = 2.65 10⁻⁶ C

Explanation:

For this exercise we use Coulomb's law

F = $k \frac{q_1q_2}{r^2}$

In this case they indicate that the load is of equal magnitude

q₁ = q₂ = q

the force is attractive because the signs of the charges are opposite

F = $k \ \frac{q^2}{r^2}$

q = $\sqrt{\frac{F \ r^2}{k} }$

we calculate

q = $\sqrt{\frac{0.7 \ 0.3^2 }{9 \ 10^9} }$

q = $\sqrt{7 \ 10^{-12} }$ Ra 7 10-12

q = 2.65 10⁻⁶ C

7 0

3 years ago

an electrically charged particle with mass m, velocity v, and charge q moves in a circle in magnetic field b. what is the formul

kolbaska11 [484]

Answer:

$r=\frac {mv}{qb}$

Explanation:

In this case, since the charged particle moves in circular motion, the centripetal force is equivalent to the magnetic force.

$\frac {mv^{2}}{r}=qvb\\\frac {mv}{r}=qb\\r=\frac {mv}{qb}$

5 0

3 years ago

A horizontal spring with spring constant 85 N/m extends outward from a wall just above floor level. A 5.5 kg box sliding across

Aloiza [94]

Answer: The box was moving with a velocity of 0.256m/s when it hit the spring

Explanation: Please see the attachments below

6 0

3 years ago

Which officeholders are elected by the electoral college

NikAS [45]

Answer:Electoral Vote

Explanation:i did it before

4 0

3 years ago

The amplitude of a paricular wave is 4.0 m. The crest to trough distance

kozerog [31]

Answer:

The crest to trough distance = 8 m

Explanation:

Given that,

The amplitude of a particular wave is 4.0 m.

We need to find the crest to trough distance.

We know that,

Amplitude = The distance from the base line to the crest or the the distance from the baseline to the trough.

It means,

Distance from crest to trough = 2(Amplitude)

= 2(4)

= 8 m

Hence, the crest to trough distance is equal to 8 m.

6 0

3 years ago