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jeka94
2 years ago
5

What is the greatest common factor (GCF) of 24 and 42?

Mathematics
1 answer:
kykrilka [37]2 years ago
7 0

Answer:

6

Step-by-step explanation:

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Steve drove at a constant rate to the beach for a vacation. In the equation below, t is the time in hours it took Steve to drive
Sindrei [870]

9514 1404 393

Answer:

  A.  64 miles per hour

Step-by-step explanation:

In a linear equation, the "unit rate" is generally the coefficient of the variable. The units of the unit rate depend on the definition of the relationship.

Here, the time t is in hours, so the "unit rate" will be <something> per hour. The answer choices suggest that the <something> is "miles". That is, the units of the equation are ...

  (miles/hour) × (hours) = miles

With numbers/variables, that is ...

  (64 miles/hour) × (t hours) = 384 miles

The unit rate is 64 miles per hour.

6 0
2 years ago
You scored a 91 on a test with bonus points. you got 4 bonus points how many points did you score before the bonus points
Alex Ar [27]
You need to subtract the bonus points form the final score: 91-4=87
3 0
3 years ago
Read 2 more answers
Anyone can u please help me.
Lina20 [59]

Answer: i cant see the pic i would help but i cant see picture

Step-by-step explanation:

5 0
2 years ago
Monday I got 3 papers for each class. I have 7 classes in total. How many papers did I get on Monday.
ANEK [815]
You got 21 papers on Monday. Because if you add 3 7 times it equals 21.





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7 0
3 years ago
Read 2 more answers
Demand The demand function for a product is given by
stira [4]

Answer:

x= -\frac{ln [\frac{5P}{8000-P}]}{0.002}

a) x= -\frac{ln [\frac{5*200}{8000-200}]}{0.002} =1027.062 \approx 1027

b) x= -\frac{ln [\frac{5*800}{8000-800}]}{0.002} =293.893 \approx 294

Step-by-step explanation:

For this case we have the following function:

P= 8000 (1- \frac{5}{5 +e^{-0.002 x}})

We can solve for x like this. First we can reorder the expression like this:

\frac{P}{8000} = 1- \frac{5}{5+e^{-0.002x}}

\frac{5}{5+e^{-0.002x}} = 1 -\frac{P}{8000} = \frac{8000-P}{8000}

\frac{40000}{8000-P} = 5 + e^{-0.002x}

Now we can apply natura log on both sids and we got:

ln[\frac{40000}{8000-P} -5] = ln e^{-0.002x}

ln [\frac{5P}{8000-P}] = -0.002x

And if we solve for x we got:

x= -\frac{ln [\frac{5P}{8000-P}]}{0.002}

Part a

For this case we can replace P = 200 and see what we got for x like this:

x= -\frac{ln [\frac{5*200}{8000-200}]}{0.002} =1027.062 \approx 1027

Part b

For this case we can replace P = 800 and see what we got for x like this:

x= -\frac{ln [\frac{5*800}{8000-800}]}{0.002} =293.893 \approx 294

4 0
3 years ago
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