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levacccp [35]
3 years ago
10

3. Consider the expressions sq root of 15, sq root of 97 and sq root of 40 Locate the approximate value of each on a number line

.
Then, estimate each square root to the nearest tenth.
Mathematics
1 answer:
Crank3 years ago
5 0

Answer:

Square root of 15

√ 15 = 3.9 (Rounding to the nearest tenth)

Square root of 97

√97 = 9.9 (Rounding to the nearest tenth)

Square root of 40

√40 = 6.3 (Rounding to the nearest tenth)

Step-by-step explanation:

Square root of 15

√ 15 = 3.9 (Rounding to the nearest tenth)

Square root of 97

√97 = 9.9 (Rounding to the nearest tenth)

Square root of 40

√40 = 6.3 (Rounding to the nearest tenth)

Location on a number line

√ 15, between + 3 and + 4, very close to +4

√40, between + 6 and + 7, close to +6

√97, between + 9 and + 10, very close to +10

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0.3(n-5)=0.4-0.2 solve for n!
mariarad [96]

Answer:

n = 5.67

Step-by-step explanation:

0.3(n-5)=0.4-0.2

0.3(n-5) = 0.2

Dividing 0.3 both side

\frac{0.3(n-5) }{0.3}  = \frac{0.2}{0.3}

n-5 = 0.67

n = 0.67+5

n = 5.67

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Step-by-step explanation:

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5 0
3 years ago
what is 12/3 as an improper fraction? a. 2/3 b. 5/3 c. 8/3 d. 6/3 user: what is 20 × 6? a. 100 b. 40 c. 12 d. 120
Sedbober [7]
1\dfrac{2}{3}=\dfrac{1\cdot3+2}{3}=\boxed{\dfrac{5}{3}}\to\fbox{b.}\\\\20\times6=6\cdot(2\cdot10)=6\cdot2\cdot10=12\cdot10=\boxed{120}\to\fbox{d.}
7 0
3 years ago
Simplify:9-1÷2÷27^2÷3​
sammy [17]

<u>First let's calculate the exponents.</u>

27^2 : 729 = 9-1\div \:2\div \:729\div \:3

<u>Now we should multiply and divide.</u>

<u />1\div2\div729\div3:\frac{1}{4374} = 9-\frac{1}{4374}<u />

<u>Now we should add and subtract.</u>

<u />9-\frac{1}{4374} :\frac{39365}{4374} =  \frac{39365}{4374}<u />

<u>Convert the improper fractions into mixed numbers.</u>

<u />8\frac{4373}{4374}<u />

<u />

<u>Answer : </u>

<u />8\frac{4373}{4374}<u />

<u />

5 0
3 years ago
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