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padilas [110]
3 years ago
12

10th grade level LT1

Mathematics
1 answer:
Slav-nsk [51]3 years ago
5 0

Answer:

<h2>? = 3.</h2>

Hope this will help you.

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NEED ASAP plz
irina [24]

Answer:

jowa di flak towo adibja nag my ja

5 0
2 years ago
A round cake has a diameter of 30 cm. What is the circumference of the<br> cake?
andre [41]

Answer: 56

Step-by-step explanation:

Just trust me I had this question on a quiz

8 0
3 years ago
Read 2 more answers
Find the exact value of cos(a+b) if cos a=-1/3 and cos b=-1/4 if the terminal side if a lies in quadrant 3 and the terminal side
maria [59]

Answer:

cos(a + b) = \frac{1}{12}(1-2\sqrt{30})

Step-by-step explanation:

cos(a + b) = cos(a).cos(b) - sin(a).sin(b) [Identity]

cos(a) = -\frac{1}{3}

cos(b) = -\frac{1}{4}

Since, terminal side of angle 'a' lies in quadrant 3, sine of angle 'a' will be negative.

sin(a) = -\sqrt{1-(-\frac{1}{3})^2} [Since, sin(a) = \sqrt{(1-\text{cos}^2a)}]

         = -\sqrt{\frac{8}{9}}

         = -\frac{2\sqrt{2}}{3}

Similarly, terminal side of angle 'b' lies in quadrant 2, sine of angle 'b' will be  negative.

sin(b) = -\sqrt{1-(-\frac{1}{4})^2}

         = -\sqrt{\frac{15}{16}}

         = -\frac{\sqrt{15}}{4}

By substituting these values in the identity,

cos(a + b) = (-\frac{1}{3})(-\frac{1}{4})-(-\frac{2\sqrt{2}}{3})(-\frac{\sqrt{15}}{4})

                = \frac{1}{12}-\frac{\sqrt{120}}{12}

                = \frac{1}{12}(1-\sqrt{120})

                = \frac{1}{12}(1-2\sqrt{30})

Therefore, cos(a + b) = \frac{1}{12}(1-2\sqrt{30})

5 0
3 years ago
What is the lowest value in the set of data represented by the following box-and-whisker plot?
solong [7]
5 because it’s the lowest
7 0
3 years ago
Read 2 more answers
Is this a function? Why or why not? *<br> 10 points<br> Captionless Image
GrogVix [38]

Answer:

Wheres the function, what do u mean by captionless image

3 0
3 years ago
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