Question

The points (–8, –4) and (6, 10) fall on a particular line. What is its equation in slope-intercept form?

Answer 1

First we need to use two point to find the slope (m)

m=(y2-y1)/(x2-x1)
X1=-8
Y1=-4
X2=6
Y2=10

m=(10-(-4))/(6-(-8))
m=(10+4)/(6+8)
m=14/14
m=1

Eq of the line formula :
Y-y1=m(x-x1)
Y-(-4)=1(x-(-8))
Y+4=x+8
Y=x+4