Question

Distance between (2,2) and (7,5)

Answer 1

You use a modification of the pythagorean theorem to find
pythagoreas  c^2=a^2+b^2
the easy way is you use the equation $d= \sqrt{(x1-x2)^2+(y1-y2)^2}$
so input in format (x,y) then
(2,2)
(7,5)
x1=2
y1=2
x2=7
y2=5
$d= \sqrt{(2-7)^2+(2-5)^2}$
$d= \sqrt{(-4)^2+(-3)^2}$
$d= \sqrt{16+9}$
$d= \sqrt{25}$
$d= 5$

the distance is 5 units