The height of the tank must be at least 1 foot, or 12 inches. We know the floor area (which is length x width) must be at least 400 inches. Therefore these minimum dimensions already tell us that the minimum volume is 400 x 12 = 4800 cubic inches. Since we have a maximum of 5000 cubic inches, the volume must be within the range of 4800 - 5000 cubic inches.
We can set the height at exactly 1 ft (or 12 inches). Then we can select length and width that multiply to 400 square inches, for example, L = 40 inches and W = 10 in. This gives us a tank of dimensions 40 x 10 x 12 = 4800 cubic inches, which fits all the criteria.
Π=3.14
Let's start with two digits:
3.14 = 3 14/100
= 3 7/50
= 157/50
would be the approximation for that. Let's add a few more digits:
3.1415 = 3 1415/10000
= 3 283/2000
= 6283/2000
5 (3f-8g) 2g
*distribute the 5
15f-40g×2g
(im assuming its multiplication since there are no signs that say otherwise)
15f-80g
This is not really a question tbh
