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kolbaska11 [484]
3 years ago
5

What is n x 567 = 457 + ae wgv - 48765

Mathematics
1 answer:
sesenic [268]3 years ago
3 0

Answer:

n x 567= 567n

457+ae= 457 + ae

wgv- 48765= wgv- 48765

Step-by-step explanation:

The last 2 are the same. Since they are not like terms, they can neither be added nor subtracted. Only like can be added or subtracted

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Use the confidence interval to find the estimated margin of error. Then find the sample mean. A biologist reports a confidence i
mash [69]

Complete Question

A biologist reports a confidence interval of (3.5,4.9) when estimating the mean height (in centimeters) of a sample of seedlings. What is the estimated margin of error and the sample mean?

Answer:

The  margin of error is  E = 0.7

The  sample mean is  \=  x  =  4.2

Step-by-step explanation:

from the question we are told that

   The  upper limit is  k  =  4.9

    The  lower limit is  r = 3.5

Generally the margin of error is mathematically represented as

      E =  \frac{k - r}{ 2}

      E = \frac{ 4.9  -  3.5 }{2}

     E = 0.7

Generally the sample mean is mathematically evaluated as

        \=  x = k  -  E

=>    \= x  =  4.9 - 0.7

=>    \=  x  =  4.2

4 0
3 years ago
Fernando has some nickels, dimes, and quarters that are worth a total of $3.25. He has twice as many dimes as nickels. He has 3
CaHeK987 [17]

Answer:

Number of nickels = 5

Number of dimes = 10

Number of quarters = 8

Step-by-step explanation:

Fernando has a total of nickels + dimes + quarters = 3.25$

Let the number of nickels = x

Then x(.05) + dimes(.10) + quarters(0.25) = 3.25------(1)

He has twice as many dimes as nickels

dimes = 2×nickels

dimes = 2x--------(2)

He has 3 more quarters than nickels

quarters = nickels +3

quarters = x +3------(3)

From equations 1, 2, and 3.

x(.05) + 2x(.10) + (x + 3)(.25) = 3.25

.05x + 0.2x + 0.25x + .75 = 3.25

5x + 20x + 25x + 75 = 325

50x = 325 - 75

50x = 250

x = 5

Therefore the number of nickels are 5

from equation 2 number of dimes are 10

and from equation 3 number of quarters are 8.

3 0
3 years ago
How do I find the center & radius, then write a standard equation for a,b, and c?
Ghella [55]

Firstly , we will locate centres and radius in the figures

(a)

We can see that

centre=(h,k)=(0,0)

radius=r=5

now, we can use standard equation of circle

(x-h)^2+(y-k)^2=r^2

we can plug values

we get

(x-0)^2+(y-0)^2=5^2

x^2+y^2=25

(b)

We can see that

centre=(h,k)=(5,4)

radius=r=3

now, we can use standard equation of circle

(x-h)^2+(y-k)^2=r^2

we can plug values

we get

(x-5)^2+(y-4)^2=3^2

(x-5)^2+(y-4)^2=9

(c)

We can see that

centre=(h,k)=(4,3)

radius=r=5

now, we can use standard equation of circle

(x-h)^2+(y-k)^2=r^2

we can plug values

we get

(x-4)^2+(y-3)^2=5^2

(x-4)^2+(y-3)^2=25


5 0
3 years ago
The simplified form of (2^a)(2^b)(2^c) is
Sloan [31]

Answer:

Step-by-step explanation: hope this helps!

5 0
3 years ago
Help please ASAP
yulyashka [42]

Answer: 168 sq. in.

Step-by-step explanation: the shape is a cubiod the volume is lbh=3*7*8=168

7 0
3 years ago
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