<span>f(x<0)=-f(x>0)=-x^2+5x+12
When x>0, x^2-5x-12=12, x=8, y=12
Therefore, f(x)=12 goes through point (8,12).</span>
Answer:
It's wrong because the y intercepts are different
Step-by-step explanation:
The box method is OP for these kind of questions
If I don't do a good job explaining it then I reccomend you consult the internet
Your question does not say what were your options, therefore I will answer generically: in order to understand if a point (ordered pair) is contained in a line, you need to substitute the x-component of the pair in the equation of the line and see if the calculations give you the y-component of the pair.
Example:
Your line is <span> y = 4/3x + 1/3
Let's see if <span>(0, 0) and (2, 3) </span>belong to this line
y</span> = <span>4/3·0 + 1/3 = 1/3 </span>≠ 0
Therefore, the line does not contain (0, 0)
y = 4/3·2 + 1/3 = 9/3 = 3
Therefore, the line contains (2, 3)
Answer:
y = 18 / (x + 2)²
Step-by-step explanation:
Inversely proportional
y * (x + 2)² = k
when x=1, y=2
k = 2 * (1 + 2)²
k = 18
-----------------------
y * (x + 2)² = 18
Divide both sides by (x + 2)²
y = 18 / (x + 2)²