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Kobotan [32]
3 years ago
15

HELP ME PLEASE!. 20 points!

Mathematics
1 answer:
likoan [24]3 years ago
6 0

Answer:

Part 1: She will make $1,944.00 In 4 days.

Part 2: 0.38

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Please help me with this (5th grade math)
Tanya [424]

Answer:

kenis

Step-by-step explanation:

3 0
3 years ago
Free pts!! Have a great day!
alukav5142 [94]

<em><u>Thanks !</u></em>

<em><u>Have a great day you too !! </u></em>

4 0
3 years ago
What is the end behavior of the function shown in the graph above?
Oksana_A [137]

Answer:

B

Step-by-step explanation:

6 0
2 years ago
Identify the lower class​ limits, upper class​ limits, class​ width, class​ midpoints, and class boundaries for the given freque
maw [93]

Answer:

The number of individuals included in the summary is 146.

Step-by-step explanation:

The frequency distribution table provided is as follows:

Class Intervals    Frequency

    100 - 199               24

   200 - 299              90

   300 - 399              27

   400 - 499                1

   500 - 599               4

The lower class limit it the smallest value of each class interval.

Lower class limit = {100, 200, 300, 400, 500}

The upper class limit it the highest value of each class interval.

Upper class limit = {199, 299, 399, 499, 599}

The lower class boundaries are the lower class limits decreased by 0.5 and the upper class boundaries are the upper class limits increased by 0.5.

Class boundaries:

   99.5 - 199.5  

  199.5 - 299.5

  299.5 - 399.5

  399.5 - 499.5

  499.5 - 599.5

The class width is the difference between the class boundaries of each class.

Class width = 199.5 - 99.5 = 100

So, the class width is 100.

The midpoints of a class is the average value of the boundaries of a class.

\text{Midpoint}_{100-199}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{99.5+199.5}{2}\\\\=149.5

\text{Midpoint}_{200-299}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{199.5+299.5}{2}\\\\=249.5

\text{Midpoint}_{300-399}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{299.5+399.5}{2}\\\\=349.5

\text{Midpoint}_{400-499}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{399.5+499.5}{2}\\\\=449.5

\text{Midpoint}_{500-599}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{499.5+599.5}{2}\\\\=549.5

The number of individuals included in the summary is the sum of all frequencies.

\text{Number of Individuals}=24 + 90 + 27 + 1 + 4=146

Thus, the number of individuals included in the summary is 146.

3 0
3 years ago
Read 2 more answers
Solve -2(n + 5) + 6n = 14 for n.
Murrr4er [49]

Answer:

n=6

Step-by-step explanation:

Given -> -2(n+5)+6n=14

Distributive Property -> -2n-10+6n=14

Combine like terms -> 4n-10=14

Add 10 to both sides -> 4n=24

Divide both sides by 4 -> n=6

So n=6

6 0
3 years ago
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