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Diano4ka-milaya [45]
2 years ago
5

The area that includes everything between the cell membrane and the nucleus of a cell is called the ___________.

Chemistry
2 answers:
m_a_m_a [10]2 years ago
7 0

The answer is C. Cytoplasm

happy to help!!

valkas [14]2 years ago
7 0
C. Cytoplasm is a thick solution that fills each cell and is enclosed by the cell membrane
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g In Part 7, the [Cl-] in saturated NaCl is 5.4 M at room temperature. Assume that you had 1.00 ml of the saturatedsolution, and
trapecia [35]

Answer:

7.60 M

Explanation:

Our method to solve this question is to  use the definition of molarity (M) concentration which is the number of moles per liter of solution, so for this problem we have

[Cl⁻] = # mol Cl⁻ / Vol

Now the number of moles of Cl⁻ will be sum of Cl in the 1.00 mL 5.4 M solution plus the moles of Cl⁻ in the 0.50 mL 12 M H . Since the volume in liters times the molarity gives us the number of moles we will have previous conversion of volume to liters for units consistency:

1mL x 1 L / 1000 mL = 0.001 L

0.5 mL x 1L/1000 mL = 0.0005 L

[Cl⁻]  =  0.001 L x 5.4 mol/L + 0.0005L x 12 mol/L / ( 0.001 L + 00005 L )

= 7.6 M

This is the same as the statement given in the question.

5 0
3 years ago
Based on what you’ve determined regarding one mole of sand and one mole of water, which statements must be correct?
Art [367]

Answer:

I dont know the anwer but i have the same problem

Explanation:

8 0
3 years ago
A 1.757-g sample of a / alloy was dissolved in acid and diluted to exactly 250.0 mL in a volumetric flask. A 50.00-mL aliquot of
kondor19780726 [428]

Answer:

78.14% Pb²⁺ and 21.86% of Cd²⁺

Explanation:

The first titration involves the reaction of both Pb²⁺ and Cd²⁺

In the second titration, as the buffer is HCN/NaCN, the Cd²⁺ precipitates as Cd(CN)₂ and the only ion that reacts is Pb²⁺

In the first titration:

<em>Moles EDTA = Moles Pb²⁺ and Cd²⁺:</em>

28.89mL = 0.02889L * (0.06950moles / L) = 2.008x10⁻³ moles in the aliquot. In the sample:

2.008x10⁻³ moles * (250.0mL / 50.0mL) =

0.01004 moles = Pb²⁺ + Cd²⁺ <em>(1)</em>

In the second titration:

19.07mL = 0.01907L * (0.06950mol / L) = 1.325x10⁻³ moles Pb²⁺ in the aliquot. In the sample:

1.325x10⁻³ moles Pb²⁺ * (250.0mL / 50.0mL) =

6.626x10⁻³ moles Pb²⁺

That means the moles of Cd²⁺ are:

0.01004 moles = Cd²⁺ + 6.626x10⁻³ moles Cd²⁺

3.413x10⁻³ moles Cd²⁺

The mass of each ion is:

<em>Cd²⁺ -Molar mass: 112.411g/mol-:</em>

3.413x10⁻³ moles Cd²⁺ * (112.411g / mol) =

0.384g of Cd²⁺

<em>Pb²⁺ -Molar mass: 207.2g/mol-:</em>

6.626x10⁻³ moles Pb²⁺ * (207.2g / mol) =

1.373g of Pb²⁺

The percent mass of each ion is:

1.373g Pb²⁺ / 1.757g = 78.14% Pb²⁺

And:

0.384g of Cd²⁺ / 1.757g * 100 = 21.86% of Cd²⁺

4 0
3 years ago
5
sineoko [7]

Answer:

this answer is b no u can it very easy

Explanation:

because solid and liquid can compress easily

plz support me

4 0
2 years ago
Read 2 more answers
Elements are_____.
DaniilM [7]
Elements are b) substances that are made up of only one type of atom
7 0
3 years ago
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