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Afina-wow [57]
3 years ago
10

How many grams of diphosphorus pentoxide result if 100.0 g of phosphorus are combined with sufficient oxygen?

Chemistry
1 answer:
gregori [183]3 years ago
3 0
Answer is: 230 g.
Chemical reaction: P₄ + 5O₂ → 2P₂O₅.
m(P₄) = 100 g.
M(P₄) = 4 · 31 g/mol = 124 g/mol.
n(P₄) = m(P₄) ÷ M(P₄) = 100g ÷ 124g/mol = 0,806 mol.
From reaction: n(P₄) : n(P₂O5) = 1 : 2.
n(P₂O₅) = 1,612 mol.
m(P₂O₅) = 1,612 mol · 142g/mol = 230g.
M - molar mass.
n - amount of substance.
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This question is missing the part that actually asks the question. The questions that are asked are as follows:

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[A] = [A]₀e^(-kt)

[A]₀ = initial amount
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t = time
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(a) For americium we begin with 1.00 mg of sample and must convert time to units of years, as our rate constant, k, is in units of yr⁻¹.

4 days x 1 year/365 days = 0.0110

A = (1.00)e^((-1.6x10^-3)(0.0110))
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The decay of americium is so slow that no noticeable change occurs over 4 days.

(b) We can simply plug in the information of iodine-125 and solve for A:

A = (1.00)e^(-0.011 x 4)
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Iodine-125 decays at a much faster rate than americium and after 4 days there will be a significant loss of mass.
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