Answer:
1.89 × 10^-11 M
Explanation:
Recall that;
[H^+] [OH^-] = 1 × 10^-14
[H^+] = concentration of hydronium ions
[OH^-] = concentration of hydroxide ion
Where [OH^-] = 5.3 × 10−4 M
[H^+]= 1 × 10^-14/5.3 × 10−4
[H^+]= 1.89 × 10^-11 M
Answer:
Mass, m = 19466.7 kg
Explanation:
Given that,
Portland cement concrete (PCC) has a density of 150 lb/ft³
We need to find how many kilograms of PCC are required to cast a cylindrical column 1.15 m in diameter and 7.8 m in height.
Since, 1 kg = 2.205 lb
1 lb/ft³ = 16.018 kg/m³
150 lb/ft³ = 2402.77 kg/m³
Density,
m is mass of PCC in kg and V is volume of cylinder
So, the mass of PCC required is 19466.7 kg.
Answer:
Independent variable: DIFFERENT TEMPERATURE
Explanation:
The independent variable of an experiment is the variable that the experimenter changes or manipulates in order to effect an outcome or response in the measured variable/dependent variable.
In this experiment, a scientist wants to determine how temperature affects photosynthesis. He sets up the experiment by adding 20ml of water at different temperatures to three test tubes. Hence, the independent or experimental variable is the DIFFERENT TEMPERATURES GIVEN TO EACH PLANTS IN THE TEST TUBE because it is what the experimenter changes in order to effect a measurable outcome i.e. oxygen released in each balloon as a result of photosynthesis, which is the dependent variable
Answer:
See explanation
Explanation:
If we look at the question closely, we will notice that the metal in question must be aluminum.
When aluminum is treated with sodium hydroxide, a precipitate, aluminium hydroxide is formed as follows;
Al(s) + 3NaOH(aq) ---> Al(OH)3(s) + 3Na(s)
In excess sodium hydroxide, the precipitate dissolves as follows;
Al(OH)3(s) + NaOH(aq) ----> [NaAlOH4]^-(aq)
The complex formed is sodium aluminum tetrahydroxo aluminate III.
The reaction of aluminum faith dilute hydrochloric acid occurs as follows to yield aluminum chloride;
2Al(s) + 6HCl(aq) ----> 2AlCl3(aq) + 3H2(g)
When aluminum metal is heated strongly, it yields aluminum oxide;
2Al(s) + 3O2(g) ---> Al2O3(s)
Answer:
6.4924249 × 10^-23 g you need to solve it