I wonder if you mean to write
in place of
...
If you meant what you wrote, then we have


If you meant to write
(the cube root of 256), then we could go on to have
![\sqrt[3]{256}=\sqrt[3]{16^2}=\sqrt[3]{(4^2)^2}=\sqrt[3]{4^4}=\sqrt[3]{4^3\cdot4}=4\sqrt[3]4](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B256%7D%3D%5Csqrt%5B3%5D%7B16%5E2%7D%3D%5Csqrt%5B3%5D%7B%284%5E2%29%5E2%7D%3D%5Csqrt%5B3%5D%7B4%5E4%7D%3D%5Csqrt%5B3%5D%7B4%5E3%5Ccdot4%7D%3D4%5Csqrt%5B3%5D4)
It is likely D I am not positive
Answer:what was the answer ?
Step-by-step explanation:
Co linear points have same slope
<span>Points (1,3), (-4,7), and (-29,K)
m1,2=7-3/-4-1=-4/5
m2,3=K-7/-29+4
m2,3=K-7/-25
-4/5=K-7/-25
4/5=K-7/25
4=K-7/5
20=K-7
K=27
</span>
If you divide 67 by 50 you are left with 1.34 if you turn that decimal into a percent it turns into 134%