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trasher [3.6K]
3 years ago
9

Question 15 (1 point)

Mathematics
1 answer:
insens350 [35]3 years ago
7 0
The inver of given function will be (1,-3).
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Describe and correct the error in writing an equation of the line shown
Rudiy27

Answer:

y  = -\frac{3}{5}x+4

Step-by-step explanation:

Given:

(x_1,y_1) = (0,4)

(x_2,y_2) = (5,1)

The attachment completes the question

From the attachment, the slope of the line was calculated as:

m = \frac{1-4}{0-5}

This step is inaccurate because the slope of a line is calculated using

m = \frac{y_2-y_1}{x_2-x_1}

Which gives

m = \frac{1-4}{5-0}

m = \frac{-3}{5}

m = -\frac{3}{5}

The line equation is then calculated using:

y -y_1 = m(x - x_1)

Substitute values for m, x1 and y1

y - 4 = -\frac{3}{5}(x - 0)

y - 4 = -\frac{3}{5}(x)

Open bracket

y - 4 = -\frac{3}{5}x

Make y the subject

y  = -\frac{3}{5}x+4

6 0
2 years ago
Can somebody check this and tell me if its wrong or right? ASAP
Mandarinka [93]

Answer:

Right

Step-by-step explanation:

8 0
2 years ago
What is the slope and y-intercept of the graph? (write your answer in simplest form)
Basile [38]

Answer:

ok

Step-by-step explanation:

what do u mean by the simplest form?

8 0
2 years ago
The radius of a cylinder is doubled and its height is halved. Find the ratios of their surface areas.
Inessa [10]

Answer: 1:1

Step-by-step explanation:

Let r be the radius and h be the height of a cylinder.

Formula: Curved surface area of cylinder = 2\pi rh

Now, if  radius of a cylinder is doubled and its height is halved, then new radius will be R= 2r and new height  will be  H=\dfrac{1}{2}

Now, new surface area = 2\pi RH= 2\pi(2r)\dfrac{h}{2}= 2\pi rh

Ratio of curved surface areas : \dfrac{\text{Surface area}}{\text{New surface area}}=\dfrac{2\pi rh}{2\pi rh}=\dfrac{1}{1}

Hence, the ratios of their surface areas = 1:1 .

5 0
2 years ago
<img src="https://tex.z-dn.net/?f=f%28x%29%3D%5Cfrac%7B3x-6%7D%7B5-2x%7D" id="TexFormula1" title="f(x)=\frac{3x-6}{5-2x}" alt="f
Svetradugi [14.3K]

i) The given function is

f(x)=\frac{3x-6}{5-2x}

The domain is all real values except the ones that will make the denominator zero.

5-2x=0

-2x=-5

x=2.5

The domain is all real values except, x=2.5.

ii) To find the vertical asymptote, we equate the denominator to zero and solve for x.

5-2x=0

-2x=-5

x=2.5

iii) If we equate the numerator to zero, we get;

3x-6=0

3x=6

This implies that;

x=2

iv) To find the y-intercept, we put x=0 into the given function to get;

f(0)=\frac{3(0)-6}{5-2(0)}.

f(0)=\frac{-6}{5}.

f(0)=-\frac{6}{5}.

v)

The degrees of both numerator and the denominator are the same.

The ratio of the coefficient of the degree of the numerator to that of the denominator will give us the asymptote.

The horizontal asymptote  is y=-\frac{3}{2}.

vi) The function has no common factors that are at least linear.

The function has no holes in it.

vii) This rational function has no oblique asymptotes because it is a proper rational function.

3 0
3 years ago
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