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2 years ago

I got 8.000 it isn't right Because the answer with out estimating is 17128. I need this to!

Mathematics

1 answer:

Digiron [165]2 years ago

7 0

Let's round 2141 to 2000
2000 times 8=1000 times 2 times 8=1000 times 16=16000

estimate would be 16000

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53% of U.S. adults have very little confidence in newspapers. You randomly select 10 U.S. adults. Find the probability that the

faltersainse [42]

Answer:

$P(X = 5) = 0.2423$

$P( X \ge 6 )= 0.4516$

$P( X < 4 )= 0.12694$

Step-by-step explanation:

From the question we are told that

The population proportion is p = 0.53

The sample size is n = 10

Generally the distribution of the confidence of US adults in newspapers follows a binomial distribution

i.e

$X \~ \ \ \ B(n , p)$

and the probability distribution function for binomial distribution is

$P(X = x) = ^{n}C_x * p^x * (1- p)^{n-x}$

Here C stands for combination hence we are going to be making use of the combination function in our calculators

Generally the probability that the number of U.S. adults who have very little confidence in newspapers is exactly five is mathematically represented as

$P(X = 5) = ^{10}C_5 * 0.53^5 * (1- 0.53)^{10-5}$

=> $P(X = 5) = 252 * 0.04182 * 0.023$

=> $P(X = 5) = 0.2423$

Generally the probability that the number of U.S. adults who have very little confidence in newspapers is at least six is mathematically represented as

$P( X \ge 6 )= P( X = 6) + P( X = 7) + P( X = 8) + P( X = 9) + P( X = 10)$

=> $P( X \ge 6 )= [^{10}C_6 * [0.53]^6 * (1- 0.53)^{10-6}] + [^{10}C_7 * [0.53]^7 * (1- 0.53)^{10-7}] + [^{10}C_8 * [0.53]^8 * (1- 0.53)^{10-8}] + [^{10}C_9 * [0.53]^9 * (1- 0.53)^{10-9}] + [^{10}C_{10} * [0.53]^{10} * (1- 0.53)^{10-10}]$

=> $P( X \ge 6 )= [0.227] + [0.1464] + [0.0619] + [0.0155] + [0.00082]$

=> $P( X \ge 6 )= 0.4516$

Generally the probability that the number of U.S. adults who have very little confidence in newspapers is less than four is mathematically represented as

$P( X < 4 )= P( X = 3) + P( X = 2) + P( X = 1) + P( X = 0)$

=> $P( X < 4 )= [^{10}C_3 * 0.53^3 * (1- 0.53)^{10-3}] + [^{10}C_2 * 0.53^2 * (1- 0.53)^{10-2}] + [^{10}C_1 * 0.53^1 * (1- 0.53)^{10-1}] + [^{10}C_0 * 0.53^0 * (1- 0.53)^{10-0}]$

=> $P( X < 4 )= 0.09051 + 0.03 + 0.0059 + 0.000526$

=> $P( X < 4 )= 0.12694$

5 0

2 years ago

Choose the equivalent system of linear equations that will produce the same solution as the one given below:

skelet666 [1.2K]

D is the answer as the both have solution x=-2 y=3
14x=-28 12(-2)-3y=-33
x=-2 -3y=-9
y=3
from the given equation
4x-y=11 eq 1
2x+3y=5 eq 2
x=y-11/4 from equation 1
subsitute this value of x in equation 2
2(y-11/4)+3y=5
y-11+6y=10
7y-11=10
y=3
subsitude this value of y in equation (x=y-11/4)
so x= -2
thus same solution so ANSWER IS D

3 0

2 years ago

On 34 acres of land there are total of 8942 trees. If spread evenly how many trees are on each acre?

goldenfox [79]

263 trees on each acre

3 0

3 years ago

Read 2 more answers

How can i find the volume of this figure help please

valentinak56 [21]

Answer:

The answer is 463 inch cubed

Step-by-step explanation:

you do 8 x 8 x 7 which will give you 448 volume for just the cube.

then you do 5 x 3 x 1 = 15

you add 448 with 15 you will get 463

6 0

2 years ago

The diagram represents a dilation with a center at P. If the scale factor of e dilation is K, which statement about the diagram

boyakko [2]

Answer:

C is correct. If the scale factor is greater than 1, the image is an enlargement. The segment UT could be an enlargement of the segment ST.

Step-by-step explanation:

A. If > 1, then the image of could be .

B. If 0 < < 1, then the image of could be . ( If the scale factor is between 0 and 1, the image is a reduction )

C. If > 1, then the image of could be .

D.If = 2, then the image of is itself.

A is not correct. If the scale factor is between 0 and 1, the image is a reduction.

B is not correct. If the scale factor is between 0 and 1, the image is a reduction.

C is correct. If the scale factor is greater than 1, the image is an enlargement.

D is not correct. If the scale factor is 1, the figure and the image are congruent.

8 0

2 years ago