Is it weird to date someone older than u?
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1)Tthe first answer is that as x increases the value of p(x) approaches a number that is greater than q (x).
2) the y-intercept of the function p is greater than the y-intercept of the function q.
Explanation:
1) Value of the functions as x increases.
Function p:
As x increases, the value of the function is the limit when x → ∞.
Since [2/5] is less than 1, the limit of [2/5]ˣ when x → ∞ is 0, and the limit of p(x) is 0 - 3 = -3.
While in the graph you see that the function q has a horizontal asymptote that shows that the limit of q (x) when x → ∞ is - 4.
Then, the first answer is that as x increases the value of p(x) approaches a number that is greater than q (x).
2) y - intercepts.
i) To determine the y-intercept of the function p(x), just replace x = 0 in the equation:
p(x) = [ 2 / 5]⁰ - 3 = 1 - 3 = - 2
ii) The y-intercept of q(x) is read in the graph. It is - 3.
Then the answer is that the y-intercept of the function p is greater than the y-intercept of the function q.
1)Tthe first answer is that as x increases the value of p(x) approaches a number that is greater than q (x).
2) the y-intercept of the function p is greater than the y-intercept of the function q.
Explanation:
1) Value of the functions as x increases.
Function p:
As x increases, the value of the function is the limit when x → ∞.
Since [2/5] is less than 1, the limit of [2/5]ˣ when x → ∞ is 0, and the limit of p(x) is 0 - 3 = -3.
While in the graph you see that the function q has a horizontal asymptote that shows that the limit of q (x) when x → ∞ is - 4.
Then, the first answer is that as x increases the value of p(x) approaches a number that is greater than q (x).
2) y - intercepts.
i) To determine the y-intercept of the function p(x), just replace x = 0 in the equation:
p(x) = [ 2 / 5]⁰ - 3 = 1 - 3 = - 2
ii) The y-intercept of q(x) is read in the graph. It is - 3.
Then the answer is that the y-intercept of the function p is greater than the y-intercept of the function q.
<u>Answer:</u>
a) 3.675 m
b) 3.67m
<u>Explanation:</u>
We are given acceleration due to gravity on earth =
And on planet given =
A) <u>Since the maximum</u><u> jump height</u><u> is given by the formula </u>
Where H = max jump height,
v0 = velocity of jump,
Ø = angle of jump and
g = acceleration due to gravity
Considering velocity and angle in both cases
Where H1 = jump height on given planet,
H2 = jump height on earth = 0.75m (given)
g1 = 2.0 and
g2 = 9.8
Substituting these values we get H1 = 3.675m which is the required answer
B)<u> Formula to </u><u>find height</u><u> of ball thrown is given by </u>
which is due to projectile motion of ball
Now h = max height,
v0 = initial velocity = 0,
t = time of motion,
a = acceleration = g = acceleration due to gravity
Considering t = same on both places we can write
where h1 and h2 are max heights ball reaches on planet and earth respectively and g1 and g2 are respective accelerations
substituting h2 = 18m, g1 = 2.0 and g2 = 9.8
We get h1 = 3.67m which is the required height