Answer:
2.75 seconds.
Step-by-step explanation:
We have been given that a ball is dropped from the ground. T represents the time in seconds.
To find the time when the ball was in air, we will equate height of ball with 0 and solve for t.
Upon dividing both sides by 4, we will get:
Since our given function is a downward opening parabola, so ball will be in air between both t-intercepts.
Since the ball touches the ground at 2.75 seconds, therefore, the ball would be in air for approximately 2.75 seconds.
1/2x+9=2x/2-1. I hope this meets ur criteria. It works and equals 20.
The answer for this equation is q=5
The equation of the line in its generic form is:
y = mx + b
Where,
m = (y2-y1) / (x2-x1)
For (-1, 3) and (0, 1):
We look for the value of m:
m = (1-3) / (0 - (- 1))
m = (- 2) / (0 + 1)
m = -2
We look for the value of b:
1 = m (0) + b
b = 1
The line is:
y = -2x + 1
For (1, 4) and (0, 2):
We look for the value of m:
m = (2-4) / (0-1)
m = (- 2) / (- 1)
m = 2
We look for the value of b:
2 = m (0) + b
b = 2
The line is:
y = 2x + 2
The system of equations is:
y = -2x + 1
y = 2x + 2
Answer:
the system has one solution
Answer:
11
Step-by-step explanation:
6 : 1
66 : X
X/66 = 1/6
X = 11
