1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
tatyana61 [14]
3 years ago
7

What is the mass of 6.2 mil of K2CO3

Chemistry
1 answer:
Oksi-84 [34.3K]3 years ago
6 0

Answer:

6.2 moles of K2CO3 can be converted to 856.8741 grams.

You might be interested in
How much force is needed to make a 60 kg object accelerate at a rate of 2.0 m/s2?
marusya05 [52]

Answer: 120N

Explanation:

Given variables are:

force needed = ?

mass of object = 60 kg

acceleration = 2.0 m/s²

Since the magnitude of force depends on the mass of the object and the acceleration by which it moves.

i.e Force = mass x acceleration

Force = 60 kg x 2.0 m/s²

Force = 120 N

Thus, 120 Newton of force is needed to make 60 kg object accelerate at a rate of 2.0 m/s²

7 0
3 years ago
Help asap i need help
zalisa [80]

Answer:

from producers to consumers

Explanation:

Energy is transferred between organisms in food webs from producers to consumers. The energy is used by organisms to carry out complex tasks. The vast majority of energy that exists in food webs originates from the sun and is converted (transformed) into chemical energy by the process of photosynthesis in plants

Short answer, don't know but i'm sure the answer is up here

3 0
2 years ago
Pls tell me how to solve this!
Anna35 [415]

Answer:

12 seconds

Explanation:

Time taken by 50cm³ of oxygen to diffuse from pinhole

= 1 minute = 60 seconds

⠀

⠀

\textsf{ Rate of oxygen} \sf (O_2) = \frac{50}{60}

⠀

⠀

⠀

<u>Let</u><u> </u><u>time</u><u> </u><u>taken</u><u> </u><u>by</u><u> </u><u>5</u><u>0</u><u>c</u><u>m</u><u>³</u><u> </u><u>of</u><u> </u><u>hydrogen</u><u> </u><u>to</u><u> </u><u>diffuse</u><u> </u><u>from</u><u> </u><u>pinhole</u><u> </u><u>=</u><u> </u><u>t</u><u> </u><u>seconds</u>

⠀

⠀

\textsf {Rate of hydrogen } \sf(H_2) =  \frac{50}{t}

⠀

⠀

⠀

According to the formula

\sf \frac{Rate  \: of  \: hydrogen(H_2)}{Rate \:  of \:  oxygen(O_2) }  =   \sqrt{ \frac{Molar \: mass \: of \:  O_2}{Molar  \: mass \: of \: H_2} }

⠀

⠀

\large  \sf  \frac{50}{t}  \div  \frac{50}{60}  =  \sqrt{ \frac{\cancel{32}\small 16}{\cancel2} }  \\  \\  \sf   \large \frac{ \cancel{50}}{t}  \times  \frac{60}{ \cancel{50}}  =  \sqrt{16}  \\  \\  \sf   \large \frac{60}{t}  = 4 \\  \\  \sf \large  \frac{ \cancel{60} \:  \small12}{ \cancel4}  = t \\  \\    \large \underline{ \boxed{ \tt t = 12 \: seconds}}

⠀

⠀

⠀

<h3><u>Henceforth</u><u>,</u><u> </u><u>the</u><u> </u><u>time</u><u> </u><u>taken</u><u> </u><u>by</u><u> </u><u>5</u><u>0</u><u>c</u><u>m</u><u>³</u><u> </u><u>of</u><u> </u><u>hydrogen</u><u> </u><u>to</u><u> </u><u>diffuse</u><u> </u><u>is</u><u> </u><u>1</u><u>2</u><u> </u><u>seconds</u><u>.</u><u> </u></h3>

⠀

⠀

<h2>Thank you!</h2>
8 0
2 years ago
Please help me ASAP I’ll mark Brainly
expeople1 [14]

Answer:

- Oil Energy is a Major Source of Pollution and Damage Made to the Environment Every Year.

- Oil Like the Other Fossil Fuels Is A Finite Resource.

- Emissions Produced by Oil Causes Acid Rain

-Plastic is One of the Products Obtained Through Oil Refining.

- Working in the Oil Sector Can Be a Dangerous Activity.

hope this is good enough :)

3 0
3 years ago
Read 2 more answers
Which one of the following statements is true?A. Some real gases have lower pressures than that calculated for the ideal gas bec
NNADVOKAT [17]

Answer:

A. Some real gases have lower pressures than that calculated for the ideal gas because of attraction between molecules.

Explanation:

At room temperature and moderately low pressures ideal gases among other assumptions:

I. Do not attract or repel each other.

II. Have negligible volume relative to the volume of the containing vessel.

Thus the ideal gas equation:

PV = nRT

Where P = gas pressure = gas molecules' collision with the walls of the containing vessel.

V = volume occupied by the gas sample.

T = Kelvin temperature of the gas

n = number of mole of the gas present.

R = proportionality constant called the molar gas constant = 0.0821 L. atm/K.mol.

However, at low temperatures and high pressures, gases exhibit real behaviors and the

I. attractive forces between the gas molecules may not be negligible.

II. volume of the gas molecules may not be negligible relative to the volume of the container.

At low temperatures, the average kinetic energy of the gas molecules decreases which prevents the molecules breaking free from their molecular attraction.

At high pressures, the density of the gas increases and the molecules come closer to one another. This increases the intermolecular forces between the gas molecules, increases the number of molecules found per unit volume and lowers their speed moving towards the containing wall thus lowering the pressure the gas would exert than if it were in an ideal behavior.

van der Waals corrected the actual pressure and volume of real gases as follows:

( P + an^2/V^2 ) ( V – nb ) = nRT

Where n^2/V^2 = number of molecules per unit volume.

P = observed pressure.

( V – nb ) = effective volume of the gas.

6 0
3 years ago
Other questions:
  • An organic acid is composed of carbon (45.45%), hydrogen (6.12%), and oxygen (48.44%). Its molar mass is 132.12 g/mol. Determine
    5·2 answers
  • Calculate the number of moles in 456 g of lead, Pb
    10·1 answer
  • Is the flame test a test for the cation (metal listed first) or the anion (nonmetal listed second)?
    5·1 answer
  • How would the moon appear from earth if the moon did not rotate?
    10·1 answer
  • Convert 26 kg/L into g/mL
    11·1 answer
  • This is a regulation of the internal environment of an organism.
    12·1 answer
  • which tool was mostly likely used in a procedure if the lab report shows that approximately 300 ml of water was used
    10·1 answer
  • Bacteria have a nucleus but no nuclear membrane *<br><br> True<br> False
    11·1 answer
  • In an experiment, what is an independent variable?
    5·1 answer
  • A 80.0 g sample of copper (specific heat = 0.20 J/g °C ) is heated and then added to 100 g water at 22.3 °C. The final temperatu
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!