A chemical formula shows the kinds and numbers of <u>atoms</u> in the smallest representative unit of a substance.
<u>Explanation:</u>
In chemistry, a formula unit is the empirical formula of "ionic or covalent network solid compound" that is used as an independent entity for "stoichiometric calculations". This formula is a representation of a molecule that uses chemical symbols.
The unit is the lowest whole number ratio of ions represented in an ionic compound. It gives the numbers of atoms representing the "smallest representative" unit of a substance. The number of atoms also tells us about the chemical and physical properties of the compound formed.
Answer:
Theoretical yield = 2.5 g
Explanation:
Given data:
Mass of sodium = 79.7 g
Mass of water = 45.3 g
Theoretical yield of hydrogen gas = ?
Solution:
Chemical equation:
2Na + 2H₂O → 2NaOH + H₂
Number of moles of sodium:
Number of moles = mass/ molar mass
Number of moles = 79.7 g / 23 g/mol
Number of moles = 3.5 mol
Number of moles of water:
Number of moles = mass/ molar mass
Number of moles = 45.3 g / 18g/mol
Number of moles = 2.5 mol
Now we will compare the moles of hydrogen gas with water and sodium.
H₂O : H₂
2 : 1
2.5 : 1/2×2.5 =1.25 mol
Na : H₂
2 : 1
3.5 : 1/2×3.5 =1.75 mol
water will be limiting reactant.
Theoretical yield:
Mass = number of moles × molar mass
Mass = 1.25 mol × 2 g/mol
Mass = 2.5 g
Answer:
a nitrogen containing base, a pentose (five-carbon) sugar, and one or more phosphate groups
Explanation:
found this information on, newworldencyclopedia.com
Heating up, mostly. Solid can be heated to liquid, then to gas, then eventually to plasma.
Answer:
The answer to your question is 0.64 M
Explanation:
Data
Sucrose C₁₂H₂₂O₁₁ mass = 7.633 g
volume = 25 ml
Molarity = ?
Process
1.- Calculate the molar weight of Sucrose
C₁₂H₂₂O₁₁ = (12 x 12) +(22 x 1) + (11 x 16)
= 144 + 22 + 176
= 342 g
2.- Calculate the moles of sucrose
342 g ------------------ 1 mol
7.633 g --------------- x
x = (7.633 x 1) / 342
x = 0.0223 moles
3.- Calculate the molarity
Molarity = moles / volume (L)
Molarity = 0.0223 / 0.035
Molarity = 0.64
