Answer:
The correct answer is option a.
Explanation:
Equilibrium concentration cadmium ions = ![[Cd^{2+}]=0.0585 M](https://tex.z-dn.net/?f=%5BCd%5E%7B2%2B%7D%5D%3D0.0585%20M)
Equilibrium concentration fluoride ions = ![[F^{-}]=0.117 M](https://tex.z-dn.net/?f=%5BF%5E%7B-%7D%5D%3D0.117%20M)
Molar solubility is the maximum concentration of salt present in water in ionic form beyond that no more salt will exist in its ionic form and will settle down in bottom of the solution.
The molar solubility of the solid cadmium fluoride = 0.0585 M
..[1]
Due to addition of sodium fluoride will increase concentration of fluoride in the solution.And due to common ion effect the equilibrium will shift in backward direction in [1], that is precipitation of more cadmium fluoride.
Hence, decrease in solubility will be observed.
Answer: 520.04 meters.
If you convert 350 yards to meters, you get 320.04.
320.04m + 200m = 520.04m.
Take off the .04 if necessary:)
Answer: 20 gallons of 16% and 8 gallons of 23% solution is usedfor 28 gallons of the 18 % solution.
Explanation:
According to the dilution law,
where,
= concentration of ist disinfectant solution = 16 %
= volume of pure acid solution = x gallons
= concentration of another disinfectant solution= 23%
= volume of another acid solution= (28-x) gallons
= concentration of resulting disinfectant solution = 18 %
= volume of resulting acid solution = 28 gallons
(28-x) = (28-20) = 8 gallons
Thus 20 gallons of 16% and 8 gallons of 23% solution is usedfor 28 gallons of the 18 % solution.
I’m pretty sure it’s B
Hope that helps
Answer:
10g Carbon has more particles.
Explanation:
To Find
Which has more particles 10g of C or 10g of Ca
The molar mass of carbon is 12g and Calcium is 40g.
1 mole of atom , molecule or ions contain Avagadro number (6.022×10∧23) of particles and also have a mass equal to it's molar mass.
For C,
12g C will have 6.022×10∧23 atoms
10g C will have 
×6.022×10∧23 atoms
=0.833 × 10∧23 atoms
For Ca,
1 mole Ca =40g
40g Ca will have 6.022×10∧23 atoms
10g Ca will have 
×6.022×10∧23 atoms
=0.25 × 6.022×10∧23 atoms
