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Dvinal [7]
2 years ago
13

What do neurons and protons have in common?

Chemistry
2 answers:
Dahasolnce [82]2 years ago
7 0

Answer:

Protons and neutrons have almost the same mass and are both located in the nucleus of the atom. Protons are charged particles. Neutrons are neutral particles. ... The positive charge of the protons in the nucleus is balanced by the negative charge of the electrons.

kiruha [24]2 years ago
3 0

Answer:

Protons and neutrons have almost the same mass and are both located in the nucleus of the atom

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What is the molality, m, of an aqueous solution of ammonia that is 12.83 M NH3 (17.03 g/mol)? This solution has a density of 0.9
daser333 [38]

Answer:

Molality = 18.5 m

Explanation:

Let's analyse data. We want to determine molality which means mol of solute / 1kg of solvent. (Hence we need, the moles of solute and the mass of solvent in kg)

12.83 M means molarity → mol of solute in 1L of solution

Density refers always to solution → Mass of solution / Volume of solution

1L = 1000 mL

We can determine the mass of solution with density

0.9102 g/mL = Mass of solution / 1000 mL

Mass of solution = 0.9102 g/mL . 1000 mL → 910.2 g

Let's convert the moles of solute (NH₃) to mass

12.83 mol . 17.03 g/ 1 mol = 218.5 g

We can apply this knowledge:

Mass of solution = Mass of solvent + Mass of solute

910.2 g = Mass of solvent + 218.5 g

910.2 g - 218.5 g = 691.7 g → Mass of solvent.

Let's convert the mass in g to kg

691.7 g . 1kg / 1000 g = 0.6917kg

We can determine molalilty now → 12.83 mol / 0.6917kg

Molality = 18.5 m

6 0
3 years ago
Which of the following is a product of the photosynthesis reaction?
marishachu [46]

A.glucose is a product of the photosynthesis reaction carbon dioxide is a reactant.

6 0
3 years ago
Read 2 more answers
What is the maximum amount of CO2
Wittaler [7]

Answer:

10.6 g CO₂

Explanation:

You have not been given a limiting reagent. Therefore, to find the maximum amount of CO₂, you need to convert the masses of both reactants to CO₂. The smaller amount of CO₂ produced will be the accurate amount. This is because that amount is all the corresponding reactant can produce before it runs out.

To find the mass of CO₂, you need to (1) convert grams C₂H₂/O₂ to moles (via molar mass), then (2) convert moles C₂H₂/O₂ to moles CO₂ (via mole-to-mole ratio from reaction coefficients), and then (3) convert moles CO₂ to grams (via molar mass). *I had to guess the chemical reaction because the reaction coefficients are necessary in calculating the mass of CO₂.*

C₂H₂ + O₂ ----> 2 CO₂ + H₂

9.31 g C₂H₂            1 mole               2 moles CO₂          44.0095 g
------------------  x  -------------------  x  ----------------------  x  -------------------  =
                            26.0373 g           1 mole C₂H₂              1 mole

=  31.5 g CO₂

3.8 g O₂             1 mole               2 moles CO₂          44.0095 g
-------------  x  --------------------  x  ----------------------  x  --------------------  =
                       31.9988 g              1 mole O₂                 1 mole

=  10.6 g CO₂

10.6 g CO₂ is the maximum amount of CO₂ that can be produced. In other words, the entire 3.8 g O₂ will be used up in the reaction before all of the 9.31 g C₂H₂ will be used.

8 0
1 year ago
If an experiment with 10.2 g barium chloride produced 14.5 g silver chloride, calculate thr experimental mole ratio of silver ch
Leni [432]
The  experimental  mole ratio  of silver chloride  to  barium chloride  is calculated as below

fin the mole of each compound

mole= mass/molar  mass
moles of AgCl = 14.5g/142.5 g/mol = 0.102  moles of AgCl
moles of BaCl2 = 10.2 g/208 g/mol =  0.049  moles of BaCl2

find the  mole ratio  by dividing each mole with the smallest  mole(0.049)

AgCl= 0.102/0.049 =2
BaCl2 = 0.049/0.049 =1
therefore  the mole   ratio   AgCl to  BaCl2  is  2 :1
3 0
2 years ago
Read 2 more answers
An experiment looking at structures smaller than a cell would most likely employ a
Veseljchak [2.6K]

Answer:

In a conventional optical microscope, objects less than about 200 nanometers apart cannot be distinguished from one another. ... Although electron microscopes produce a detailed image of very small structures, they cannot provide an image of the proteins that make up those structures.

4 0
3 years ago
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