Question

Calculate the molarity of a solution if there are 1.5 mol of NaCl in 2.3 L of solution

Answer 1

Answer:

0.6522 mol/L.

Explanation:

Molarity is defined as the no. of moles of a solute per 1.0 L of the solution.

M = (no. of moles of solute)/(V of the solution (L)).

∴ M = (no. of moles of solute)/(V of the solution (L)) = (1.5 mol)/(2.3 L) = 0.6522 mol/L.

Answer 2

Answer:

Molarity≅0.6522 mol/L

Explanation:

The solutions are homogeneous mixtures (that is, their properties and composition are uniform) of two or more substances. The substance that is in greater proportion is called solvent, and the substance or substances that are in a smaller proportion, solute.

The mole is an International Unit used to measure the amount of a substance.

Molarity (M) or Molar Concentration is the number of moles of solute that are dissolved in a given volume of solution. It is expressed in the units (moles / liter).

$Molarity=\frac{number of moles of solute}{solution volume}$

In this case, the solute is NaCl,and you know:

• number of moles of solute: 1.5 mol
• solution volume: 2.3 L

Then:

$Molarity=\frac{1.5 mol}{2.3 L}$

Molarity≅0.6522 mol/L