The answer is 7 remainder 2.
Answer:
3x - y = -28
Step-by-step explanation:
Given the equation y-4 = 3(x+8), distribute and simplify to get the Standard Form.
y-4 = 3(x+8)
y - 4 = 3x + 24
y = 3x + 28
-3x + y = 28
Standard form does not allow the coefficient of x to be negative so multiply the equation by -1.
3x - y = -28
2x² + 3x - 5 = 0
a=2, b=3, c=-5
D = b² - 4ac = 3² - 4*2*(-5) = 9 + 40 = 49
The given function is f(z)=3z-8 for the values f(-4), f(2) and f(z-7) respectively -20, -2 and 3z-29 respectively.
The given function is f(z)=3z-8.
We need to find the value of f(-4), f(2), f(z-7).
<h3>What is a function?</h3>
In mathematics, a function from a set X to a set Y assigns to each element of X exactly one element of Y. The set X is called the domain of the function and the set Y is called the codomain of the function.
Now to find f(-4), replace z from -4.
f(-4)=3(-4)-8=-12-8=-20
Now to find f(2), replace z from 2.
f(2)=3(2)-8=6-8=-2
Now to find f(z-7), replace z from z-7.
f(z-7)=3(z-7)-8=3z-21-8=3z-29.
Therefore, the given function is f(z)=3z-8 for the values f(-4), f(2) and f(z-7) respectively -20, -2 and 3z-29 respectively.
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Answer:
f(x) = 
+ 2x³ - 4x² - 6x + 3
Step-by-step explanation:
Note that radical zeros occur in conjugate pairs, thus
- 1 + 
is a zero then - 1 - is also a zero
is a zero then - is also a zero
Thus the corresponding factors are
(x - (- 1 + ) ), (x - (- 1 - ) ), (x - ), (x - (- )), that is
(x + 1 - ), (x + 1 + ), (x - ), (x + )
The polynomial is then the product of the roots
f(x) = (x + 1 - )(x + 1 + )(x - )(x + )
= ((x + 1)² - ()²)((x² - ()²)
= (x² + 2x + 1 - 2)(x² - 3)
= (x² + 2x - 1)(x² - 3) ← distribute
= - 3x² + 2x³ - 6x - x² + 3
= + 2x³ - 4x² - 6x + 3
