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rewona [7]
3 years ago
12

Which compound has the highest boiling point? Explain your reasoning. CH4 or CH3CH3

Physics
2 answers:
kogti [31]3 years ago
4 0

The bigger molecule has more interactions and hence the higher b.p. CH3CH2OCH2CH3 is a bigger molecule than CH4 and CH3CH3, so has more dispersion forces. It also has dipole-dipole forces due to the polarised C-O bonds. CH3OH and CH3CH2OH have hydrogen bonds due to the very electronegative O atom bonded to the H atom

God bless

Anika [276]3 years ago
3 0

Answer:

The correct answer t is ;CH_4 has a lower mass compared to CH-3CH-3 which leads to a higher boiling point.

Explanation:

Boiling point of alkanes increases with increase number of carbon atoms in the chain.

This is because along with increase in carbon atom molar mass of alkane also increases by which surface area of molecule increases which further results in increase in weak vander wall forces among the molecule. Due to this molecules associates strongly with each other and boils at high temperature

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You are holding a finishing sander with your right hand. THe sander has a flywheel which spins counterclockwise as seen from beh
ryzh [129]

Answer:

c. turn downward

Explanation:

From the information given:

To find the tendency of the sander;

We need to apply the right-hand rule torque; whereby we consider the direction of the flywheel, the direction at which the torque is acting, and the movement of the sander toward the right.

Since the flywheel of the sander is in counterclockwise movement, hence the torque direction will be outward placing on the wall. However, provided that the movement of the sander is toward the right, then there exists an opposite force that turns downward which showcases the tendency in the sander is downward.

3 0
3 years ago
A top fuel dragster with a mass of 500.0 kg starts from rest and completes a quarter mile (402 m) race in a time of 5.0 s. The d
blsea [12.9K]

The average power needed to produce this final speed is 1069.1 hp.

Mass of the dragster,  m = 500.0 kg,

Displacement travelled by the dragster,  s = 402 m,

Time taken in this travel,  t = 5.0 s,

Final velocity of the dragster,  v = 130 m/s.

Let the initial velocity of the dragster be u and acceleration be a.

Using kinematical equation,  s = ut + (1/2)at^2.

402  =  u*5  + (1/2)*a*5^2

10*u + 25*a  = 804.      ...........(1)

Using kinematical equation, v = u +at.

130 = u + 5*a

5*u + 25*a = 650.       .............(2)

Solving (1)and (2), we get,

u =  30.8 m/s.

According to work-energy theorem,

Work done = change in kinetic energy

W  = (1/2)*m*(v^2 - u^2)

W = (1/2)*500*(130^2 - 30.8^2)

W  =  3987840. J

Therefore power rating of the dragster is given by,

P  ⇒  W/t. =  3987840/5 = 797568 watt.

P  ⇒ 797568/746 =  1069.1 hp.

Learn more about Power rating here brainly.com/question/20137708

#SPJ4

5 0
2 years ago
Read 2 more answers
Which fundamental force has a small range and is always an attractive force?
erica [24]

Answer:

gravitational force is a fundamental force and also , it does have a small range and is always an attractive force.

Explanation:

5 0
3 years ago
Computers A and B implement the same ISA. Computer A has a clock cycle time of 200 ps and an effective CPI of 1.5 for some progr
lesya692 [45]

Answer:

Computer A is 1.41 times faster than the Computer B

Explanation:

Assume that number of instruction in the program is 1

Clock time  of computer A is CT_{A} =200 ps

Clock time  of computer B is CT_{B} =250 ps

Effective CPI of computer A is CPI_{A} =1.5

Effective CPI of computer B isCPI_{B} =1.7

CPU time of A is

CPU_{time}=instructions \times CPA_{A} \times CT_{A}\\CPU_{time}=1 \times 1.5 \times 200=300 sec

CPU time of B is

CPU_{time}=instructions \times CPA_{B} \times CT_{B}\\CPU_{time}=1 \times 1.7 \times 250=425 sec

Hence Computer A is Faster by \frac{425}{300} =1.41

Computer A is 1.41 times faster than the Computer B

4 0
3 years ago
D
Ber [7]

Answer:

D

Explanation:

I think you got it right

3 0
3 years ago
Read 2 more answers
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