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lara [203]
3 years ago
7

Guys im in school right now helppppppp please xoxo

Mathematics
1 answer:
ad-work [718]3 years ago
7 0

Answer:

question A: 50%

Step-by-step explanation:

For question A: the percentage is ( enroll(2014) - enrol(2012) ) / enrol(2012) for  that is 0.5 = 50%, same method for the other questions

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What are the missing parts that correctly complete the proof
bonufazy [111]

Answer:

2. \overline{AX}\cong \overline{BX}

3. PX \perp AB - definition of perpendicular

4. \angle PXA \cong \angle PXB - all right angles are congruent

6. \triangle AXP\cong \triangle BXP

7. \overline{PA} \cong \overline{PB}

Step-by-step explanation:

<u>Given: </u>Point P is the perpendicular bisector of AB

<u>Prove: </u>P is equidistant from the endpoints AB

<u>Proof.</u>

1. Point P is on the perpendicular bisector of AB - given

2.\overline{AX}\cong \overline{BX} - definition of bisector

3. PX \perp AB - definition of perpendicular

4.  \angle PXA \cong \angle PXB - all right angles are congruent

5. \overline{PX} \cong \overline{PX} - reflexive property of congruence

6. \triangle AXP\cong \triangle BXP - SAS congruency postulate

7. \overline{PA} \cong \overline{PB} - corresponding parts of congruent triangles are congruent

8. Point P is equidistant from the endpoints of AB - definition of equidistant

5 0
3 years ago
5x23x2 use properties to find the sum or protuct
sertanlavr [38]

Answer:

230

Step-by-step explanation:

use the multiplication property, it doesn't matter what wa ugh you do it because multiplication is on both sides

6 0
3 years ago
Does the graph represents a function
ohaa [14]
You could use a simple pencil test to figure it out.
Place a pencil vertically on the paper, and move it left to right or vise-versa 
When moving it make sure the pencil doesn't hit two points at once if it does it is not a function, but this is not the case

This is a function
4 0
3 years ago
Read 2 more answers
Scores on a standardized test are normally distributed with a mean of 250 and a standard a deviation of 20. Approximately what p
masha68 [24]

Answer:

You can't answer this properly without more data.

5 0
3 years ago
ITS TIMED PLEASE HELP​
Lubov Fominskaja [6]

Answer:

The graph of the function f(x)=\frac{1}{2}x^{2}-4x+5 has a minimum located at (4,-3)

Step-by-step explanation:

we know that

The equation of a vertical parabola in vertex form is equal to

f(x)=a(x-h)^{2}+k

where

a is a coefficient

(h,k) is the vertex of the parabola

If a > 0 the parabola open upward and the vertex is a minimum

If a < 0 the parabola open downward and the vertex is a maximum

In this problem

The coefficient a must be positive, because we need to find a minimum

therefore

Check the option C and the option D

Option C

we have

f(x)=\frac{1}{2}x^{2}-4x+5

Convert to vertex form

f(x)-5=\frac{1}{2}x^{2}-4x

Factor the leading coefficient

f(x)-5=\frac{1}{2}(x^{2}-8x)

f(x)-5+8=\frac{1}{2}(x^{2}-8x+16)

f(x)+3=\frac{1}{2}(x^{2}-8x+16)

f(x)+3=\frac{1}{2}(x-4)^{2}

f(x)=\frac{1}{2}(x-4)^{2}-3

The vertex is the point (4,-3) ( is a minimum)

therefore

The graph of the function f(x)=\frac{1}{2}x^{2}-4x+5 has a minimum located at (4,-3)

5 0
4 years ago
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