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3 years ago

Dwayne is finding the base of the triangle shown. It's area is 100 square meters. find his mistake and correct it.

Mathematics

2 answers:

EleoNora [17]3 years ago

8 0

$100 = \frac{1}{2} 20 \times (b) \\ 100 = 10b \\ b = 10$

DIA [1.3K]3 years ago

5 0

His mistake is in the formula for Area of triangle. The correct formula is:

$A= \frac{1}{2}(base)(height)$

Given that, Area= 100 sq. meter and height = 20 meter

So,

$100 = \frac{1}{2}(base)(20)\\ \\ 100 = (base)(10)\\ \\ base = \frac{100}{10}=10$

So, the base of the triangle will be 10 meter.

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3 years ago

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The cost of 1 watermelon and 5 oranges is $11.The cost of 3 watermelons and 5 oranges is $24.50.How much is the cost of 1 waterm

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Answer:

$6.75

Step-by-step explanation:

1: In this explanation, let's let one watermelon be w, and one orange be o.

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3: Also from the passage, 3w + 5o = $24.50

4: We can then use a simultaneous equation to work them out - both equations we have use 5 oranges.

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1w + 5o = 11 (equation 2)

5: We can now take the second equation away from the first :

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Now we know 2w = 13.5

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Hope this helps, let me know if you have any further questions :)

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2 years ago

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3 years ago

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Answer:

$\chi^2 =\frac{15-1}{25} 16 =8.96$

The degrees of freedom are given by:

$df = n-1 = 15-1=14$

The p value for this case would be given by:

$p_v =P(\chi^2$

Since the p value is higher than the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not ignificantly lower than 5 minutes

Step-by-step explanation:

Information given

$n=15$ represent the sample size

$\alpha=0.05$ represent the confidence level

$s^2 =16$ represent the sample variance

$\sigma^2_0 =25$ represent the value that we want to verify

System of hypothesis

We want to test if the true deviation for this case is lesss than 5minutes, so the system of hypothesis would be:

Null Hypothesis: $\sigma^2 \geq 25$

Alternative hypothesis: $\sigma^2$

The statistic is given by:

$\chi^2 =\frac{n-1}{\sigma^2_0} s^2$

And replacing we got:

$\chi^2 =\frac{15-1}{25} 16 =8.96$

The degrees of freedom are given by:

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The p value for this case would be given by:

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3 years ago