An explicit formula for a sequence allows you to find the value of any term in the sequence. A recursive formula for a sequence allows you to find the value of the nth term in the sequence if you know the value of the (n-1)th term in the sequence.
You simply need to compute the ratio between the length of the segment
and the length of the corresponding segment
Step-by-step explanation:

from difference of two squares:

therefore:

factorise out ¾ :

Answer:
x=2
Step-by-step explanation:
If 15x=30 and 15*2=30 then x=2
Hope this helped.
A brainliest is always appreciated.
Answer:
5yz
Step-by-step explanation:
You multiply 5 by y and z