Let a = speed of the plane A, and b = speed of plane B.
(Assume that the net effect of the wind is negligible.)
From the first sentence, the distance between A and B after each travels for 1 hour is a + b miles. From the second sentence, after 45 minutes, or 0.75 hour, the distance between A and B is 200 miles. Plane a has traveled 0.75a, while plane B has traveled 0.75b.
Hence a + b = 0.75a + 0.75b +200
==> 0.25(a + b) = 200.
==> a + b = 800.
Therefore planes A and B are 800 miles apart now.
So for this you need the two solutions to be x= -9 and x=3 then move over the numbers and put in brackets (x+9)(x-3) then multiply together x^2+9x-3x-27 then combine like terms to get x^2+6-27
Answer:
bcd= congruent property abstracted by -cdb
Step-by-step explanation:
Answer:
The option in the top right...
Step-by-step explanation:
Answer:
One solution, x = 8/9
Step-by-step explanation:
One way to solve this is to take one equation and substitute into the other and then solve. So, take y=5(x-4) and put that into the other equation.
4x + 12 = -y
4x + 12 = -(5(x-4)) <--- substitution here
4x + 12 = -5(x-4)
4x + 12 = -5x + 20 <-- simplifying
4x + 5x = 20 - 12
9x = 8
x = 8/9
