Answer:
Factors influencing population growth
Economic development. ...
Education. ...
Quality of children. ...
Welfare payments/State pensions. ...
Social and cultural factors. ...
Availability of family planning. ...
Female labour market participation. ...
Death rates – Level of medical provision
Answer:
Explanation:
The following code is written in Java and modified to do as requested. It asks the user to enter a number that is saved to the amountToChange and then uses the % operator to calculate the number of 5 dollar bills and the number of 1 dollar bills to give back. A test case has been provided and the output can be seen in the attached image below.
import java.util.Scanner;
class ComputingChange {
public static void main(String[] args) {
Scanner scnr = new Scanner(System.in);
int amountToChange;
int numFives;
int numOnes;
amountToChange = scnr.nextInt();
numFives = amountToChange / 5;
/* Your solution goes here */
numOnes = amountToChange % 5;
System.out.print("numFives: ");
System.out.println(numFives);
System.out.print("numOnes: ");
System.out.println(numOnes);
}
}
Required: program to return the largest of three numbers.
pseudocode
input parameters, int A,B,C;
int T; // temporary storage
if (A>B) T=A;
else T=B;
if (T>C) print(T);
else print(C);
Answer:
CMOS
Explanation:
CMOS stands for complementary metal oxide semiconductor. CMOS is in the design of several types of semiconductors. in most computers there are CMOS that are powered by the PC's batteries to save the memory state of date, time, and system setup parameters when the PC looses power. In the question above, given the specified parameters for the new system, a CMOS chip will serve perfectly
Answer:
a. 2100
b. 2199
Explanation:
GIven that:
The file size = 1000 MB
The payload size is = 100 bytes
The negotiated window size is = 1000 bytes.
This implies that the sliding window can accommodate maximum number of 10 packets
The sender receives an ACK 1200 from the receiver.
Total byte of the file is :
1000 MB = 1024000000 bytes
a.
Sender receives an ACK 1200 from the receiver but still two packets are still unacknowledged
=1200 + 9 * 100
= 1200 + 900
= 2100
b. What is the last byte number that can be sent without an ACK being sent by the receiver?
b. Usually byte number starts from zero, in the first packet, the last byte will be 99 because it is in 1000th place.
Thus; the last byte number send is :
= 1200 + 10 *100 -1
= 1200 + 1000-1
= 1200 + 999
= 2199
