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Monica [59]
3 years ago
14

Systematic or Random Error? -This type of error affects overall accuracy but does not necessarily affect precision. This type of

error affects precision but does not necessarily affect overall accuracy. This type of error occurs if you use a buret that was calibrated incorrectly when it was made. You can minimize this type of error by taking repeated measurements.
Chemistry
1 answer:
love history [14]3 years ago
3 0

Answer:

<em>This type of error affects overall accuracy but does not necessarily affect precision.</em> - Systematic error

<em>This type of error affects precision but does not necessarily affect overall accuracy.</em> - Random error

<em>This type of error occurs if you use a buret that was calibrated incorrectly when it was made.</em> - Systematic error

<em>You can minimize this type of error by taking repeated measurements.</em> - Random error

Explanation:

<em>Systematic errors are errors that are attributable to instrument being used during measurement or consistent incorrect measurement during a research</em>. They are consistently and repeatedly committed during measurements and therefore affect the overall accuracy of measurements. A person committing systematic error can have precise repeated measurement but will be far from being accurate.

R<em>andom errors on the other hand has no pattern and are usually unavoidable because they cannot be predicted.</em> When sufficient replicate measurements are made, such errors are reduced to the barest minimum and usually do not affect the overall accuracy of measurements.

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I notice that it's extremely hot after it has been sitting in thr sun for a while. The sun's rays have been directly shining on the car because the car was in the sun's Ray's directly. If the car's windows were to be left open, it would be less hot but still be hot if the rays of the sun were directly on the car.

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Write the chemial formula for H3PO4​
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The movement of air caused by differences in air pressure is __________________.
chubhunter [2.5K]

Answer:

wind

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3 years ago
Read 2 more answers
he standard enthalpies of formation for S (g), F (g), SF4 (g), and SF6 (g) are +278.8, +79.0, -775, and -1209 kJ per mole, respe
JulsSmile [24]

Answer:

+60.54 kJ/mol

Explanation:

The enthalpy of formation of a compound is the sum of the enthalpies of the formation of its constituents and the bond of them. To form a compound, energy must be lost, so, they're negative.

For SF4, the enthalpy is formed by the energy of one S, two F, and 4 S-F bond (Hb):

H = - (278.8 + 4*79.0 + 4*Hb)

-775 = -(594.8 + 4Hb)

594.8 + 4Hb = 775

4Hb = 180.2

Hb = +45.05 kJ/mol

For SF6, the enthalpy is formed by the energy of one S, six F, and 6 S--F bonds (Hb):

H = -(278.8 + 6*79.0 + 6*Hb)

-1209 = -(752.8 + 6Hb)

752.8 + 6Hb = 1209

6Hb = 456.2

Hb = +76.03 kJ/mol

Thus, the energy of S--F bond must be the average of these two:

(45.05 + 76.03)/2 = +60.54 kJ/mol

3 0
3 years ago
Determine the mass of each of t he following:
EastWind [94]

Explanation:

Mass of compounds = Moles of compound × Molecular mass of compound

a) Moles of LiCl = 2.345 mol

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Mass of 2.345 moles of LiCl = 2.345 mol × 42.5 g/mol = 99.6625 g

b) Moles of acetylene = 0.0872 mol

Molecular mass of acetylene= 26 g/mol

Mass of 0.0872 moles acetylene= 0.0872 mol × 26 g/mol = 2.2672 g

c) Moles of sodium carbonate= 3.3\times 10^{-2}mol

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Mass of  3.3\times 10^{-2}mol sodium carbonate

=  3.3\times 10^{-2}mol\times 106 g/mol= 3.498 g

d) Moles of fructose = 1.23\times 10^3 mol

Molecular mass fructose= 180 g/mol

Mass of  1.23\times 10^3 mol fructose

=  1.23\times 10^3mol\times 180 g/mol = 221,400 g

e) Moles of  FeSO_4(H_2O)_7=0.5758 mol

Molecular mass of FeSO_4(H_2O)_7 =278 g/mol

Mass of  1.23\times 10^3 mol fructose

=  0.5758 mol\times 278 g/mol= 160.0724 g

3 0
3 years ago
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