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Evgen [1.6K]
3 years ago
8

Elements occur in a number of isotopic forms. In this problem, you will learn about the notation used to distinguish different i

sotopes.How many protons Z and how many neutrons N are there in a nucleus of the most common isotope of silicon, 28/14Si?
Chemistry
1 answer:
maksim [4K]3 years ago
7 0

Answer:

  • <em>There are </em><u><em>14 protons</em></u><em> (Z) and </em>14 neutrons<em> (N) in a nucleus of the most common isotope of silicton.</em>

Explanation:

The notation of the <em>most common isotope of silicon</em> is:

  • ^{28}_{14}Si

The superscript, 28, to the left of the chemical symbol, Si, is the mass number, usually identified with the symbol A, and it is the sum of the protons and neutrons.

The subscript, 14, to the left of the chemical symbolr, Si, is the atomic number, Z, which is the number of protons.

Then, you have this equation:

  • mass number = number of protons + neutrons, or, in symbols:

  • A = Z + N

The number of protons is the same for any isotope of the same element. This is, all the isotopic forms of silicon have the same number of prtons: 14

The number of neutrons is determined from the equation A = Z + N, solving for N:

  • N = A - Z = 28 - 14 = 14.

Hence, the most common isotope of silicon has 14 protons and 14 neutrons.

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Calculate the volume of 5.00 mol of helium at 120C and 1520 mm Hg
levacccp [35]

Answer:

80.7 L

Step-by-step explanation:

This looks like a case where we can use the Ideal Gas Law to calculate the volume.

pV = nRT       Divide both sides by p

V = (nRT)/p

=====

Data:

n = 5.00 mol

R = 0.082 06 L·atm·K⁻¹mol⁻¹

T = (120 +273.15) K = 393.15K

p = 1520 mmHg × 1 atm/760 mmHg = 2.00 atm

=====

Calculation:

V = (5.00 × 0.082 06 × 393.15)/2.00

V = 161.3/2.00

V = 80.7 L  

4 0
3 years ago
If 500.0 mL of 0.10 M Ca2+ is mixed with 500.0 mL of 0.10 M SO42−, what mass of calcium sulfate will precipitate? Ksp for CaSO4
statuscvo [17]

Answer:

The mass of calcium sulfate that will precipitate is 6.14 grams

Explanation:

<u>Step 1:</u> Data given

500.0 mL of 0.10 M Ca^2+ is mixed with 500.0 mL of 0.10 M SO4^2−

Ksp for CaSO4 is 2.40*10^−5

<u>Step 2:</u> Calculate moles of Ca^2+

Moles of Ca^2+ = Molarity Ca^2+ * volume

Moles of Ca^2+ = 0.10 * 0.500 L

Moles Ca^2+ = 0.05 moles

<u>Step 3: </u>Calculate moles of SO4^2-

Moles of SO4^2- = 0.10 * 0.500 L

Moles SO4^2- = 0.05 moles

<u>Step 4: </u>Calculate total volume

500.0 mL + 500.0 mL = 1000 mL = 1L

<u>Step 5: </u> Calculate Q

Q = [Ca2+] [SO42-]  

[Ca2+]= 0.050 M   [O42-]

Qsp = (0.050)(0.050 )=0.0025 >> Ksp

This means precipitation will occur

<u> Step 6:</u> Calculate molar solubility

Ksp = 2.40 * 10^-5 = [Ca2+][SO42-] =(x)(x)

2.40 * 10^-5 = x²

x = √(2.40 * 10^-5)

x = 0.0049 M = Molar solubility

<u> Step 7:</u> Calculate total CaSO4 dissolved

total CaSO4 dissolved = 0.0049 M * 1 L * 136.14 mol/L = 0.667 g

<u>Step 8:</u> Calculate initial mass of CaSO4

Since initial moles CaSo4 = 0.050

Initial mass of CaSO4 = 0.050 * 136.14 g/mol

Initial mass of CaSO4 = 6.807 grams

<u>Step 9:</u> Calculate mass precipitate

6.807 - 0.667 = 6.14 grams

The mass of calcium sulfate that will precipitate is 6.14 grams

5 0
3 years ago
Can a tank of oxygen gas ever be half empty? explain
Brilliant_brown [7]
Im sorry about my answer a while ago.

answer: it will not be half empty ever. because any gas take all the space of the tank. molecules are everywhere they take so much space.
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Near water, change in elevation, or change in latitude.

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B I tjinksjwkzosmznqosnsnw
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