Please see attached file for the triangle’s figure:
Going with the image attached, if DE is parallel to BC<span>
then
<span>4: (4 + 5) = 6 : (6 + 7).
Therefore, the inequality that she will use to contradict the assumption</span>
is 4:9 ≠ 6:13</span>.
To add, a relation that holds
between two values when they are different in mathematics is called an inequality. A is not equal to b also means the notation a ≠ b.
<span><span>
</span>Inequalities are governed by the following properties<span>:
Transitivity</span></span>
Converse
Addition and subtraction
Multiplication and division
Additive inverse
Multiplicative inverse
<span>Applying a function to both sides</span>
This image has the step by step solution
Answer:
New mean=71.32
Step-by-step explanation:
The expression for the total initial score is;
T=M×S
where;
T=total initial score
M=mean score
S=number in the set
replacing;
T=unknown
M=72
S=17
replacing;
T=72×17=1,224
The total initial score=1,224
Determine the total score by;
total score=total initial score+total final score
where;
total initial score=1,224
total final score=(68+63)=131
replacing;
total score=1,224+131=1,355
Determine the new mean;
New mean=total score/new number
where;
total score=1,355
new number=(17+2)=19
replacing;
new mean=1,355/19=71.32
You can solve this by using "similar triangles".
In triangle ABC, we are looking for side AC which is x. Side AC is similar to side DF in triangle EDF.
You can solve for side x by picking two sides in triangle ABC and their corresponding sides in triangle EDF. This is what I mean:
![\frac{AC}{BC} = \frac{DF}{EF}](https://tex.z-dn.net/?f=%20%5Cfrac%7BAC%7D%7BBC%7D%20%3D%20%20%5Cfrac%7BDF%7D%7BEF%7D%20)
Substitute for the values of AC, BC, DF and EF:
![\frac{x}{4} = \frac{11}{8} \\ \\ 8x = 4 \times 11 \\ \\ x = \frac{44}{8}](https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%7D%7B4%7D%20%20%3D%20%20%5Cfrac%7B11%7D%7B8%7D%20%20%5C%5C%20%20%5C%5C%208x%20%3D%204%20%5Ctimes%2011%20%5C%5C%20%20%5C%5C%20x%20%3D%20%20%5Cfrac%7B44%7D%7B8%7D%20)
![x = 5.5 \: units](https://tex.z-dn.net/?f=x%20%3D%205.5%20%5C%3A%20units)
To solve for y, do the same thing. Pick two sides on triangle ABC and their corresponding sides in triangle DEF.
![\frac{AB}{BC} = \frac{DE}{EF}](https://tex.z-dn.net/?f=%20%5Cfrac%7BAB%7D%7BBC%7D%20%20%3D%20%20%5Cfrac%7BDE%7D%7BEF%7D%20)
Substitute for the values and solve:
![\frac{3}{4} = \frac{y}{8}](https://tex.z-dn.net/?f=%20%5Cfrac%7B3%7D%7B4%7D%20%20%3D%20%20%5Cfrac%7By%7D%7B8%7D%20)
![4y = 24 \\ \\ y = 6 \: units](https://tex.z-dn.net/?f=4y%20%3D%2024%20%5C%5C%20%20%5C%5C%20y%20%3D%206%20%5C%3A%20units)
We have the value x to be 5.5 units and y to be 6 units.
The term in the expansion:
T ( k+1) = n C k * A^(n-k) * B^k.
In this case: n = 11, k + 1 = 8, so k = 7.
A = x, B = - 3 y
T 8 = 11 C 7 * x^(11-7) * ( - 3 y )^7 =
=( 11 *10 * 9 * 8 * 7 * 6 * 5 ) / ( 7 * 6 * 5 * 4 * 3 * 2 * 1 )* x^4 * ( - 2,187 y^7 ) =
= 330 * ( - 2,187 ) x^4 y^7 = - 721,710 x^4 y^7
Answer: The 8th term in expansion is