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mel-nik [20]
3 years ago
13

Charges build in storm _________ and then jump to the ground

Chemistry
2 answers:
Elena L [17]3 years ago
6 0
They build in storm clouds
Bogdan [553]3 years ago
4 0
Charges build in storm clouds and then jump to the ground. 
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If the ph of a solution is 6.2 what would the poh be
horsena [70]
PH + poH = 14
6.2 +poH = 14
poH = 7.8
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2. B) electrical chemical thermal mechanical 
3. B) light, sound, and heat
4. A) light energy from the sun
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The best thermometer to use where temperatures drop below -39°C (-38.2°F) is:_______.
xxTIMURxx [149]

Answer:

The best thermometer to use for this temperature is the alcohol-in-a -glass thermometer.

Explanation:

The alcohol thermometer is a type of thermometer which uses ethanol as its thermometric liquid. This has some advantages at low temperatures because ethanol freezes at about −114.9 °C  that is (−174.82 °F).

Due to its low freezing point, it can still function effectively as a thermometric liquid, expanding and contracting properly based on the applied heat,  when dealing with temperature measurements that are at about -38.2°F.

4 0
4 years ago
What is the Molar Mass of 2.4g of oxygen
Anastasy [175]
<span>We have a sample of a gas which is a compound of carbon and oxygen. Chemical analysis shows that it contains 2.4 g of carbon and 6.4 g of oxygen. What is its formula?</span>
3 0
4 years ago
The equations are 2NaHCO3 -&gt; Na2CO3 + CO2 + H20, NaHCO3 -&gt; NaOH + CO2, 2NaHCO3 -&gt; Na2O + 2CO2 + H20
cricket20 [7]

Answer:

The product made is Na2CO3.

The % yield is 91.8 %

Explanation:

Step 1: Data given

Mass of baking soda (NaHCO3) = 5.0 grams

Molar mass of NaHCO3 = 84.0 g/mol

Each of the equations calculated is left with 2.4g of NaOH, 1.86 g Na2O, and 3.18g Na2Co3.

Step 2: The balanced equations

2NaHCO3 → Na2CO3 + CO2 + H20

NaHCO3 → NaOH + CO2

2NaHCO3 → Na2O + 2CO2 + H20

Step 3: Calculate moles NaHCO3

Moles NaHCO3 = mass NaHCO3 / molar mass NaHCO3

Moles NaHCO3 = 5.0 grams / 84.0 g/mol

Moles NaHCO3 = 0.060 moles

Step 4: Calculate moles of products

For 2 moles NaHCO3 we'll have 1 mol Na2CO3

For 0.060 moles NaHCO3 we'lll have 0.060 / 2 = 0.030 moles Na2CO3

For  1 mol NaHCO3 we'll have 1 mol NaOH

For 0.060 moles NaHCO3 we'll have 0.060 moles NaOH

For 2 moles NaHCO3 we'll have 1 mol Na2O

For 0.060 moles NaHCO3 we'll have 0.030 moles Na2O

Step 5: Calculate mass of products

Mass = moles * molar mass

Mass of Na2CO3 = 0.030 moles * 105.99 g/mol = 3.18 grams

Mass of NaOH = 0.060 moles * 40.0 g/mol = 2.4 grams

Mass of Na2O = 0.030 moles *61.98 g/mol = 1.86 grams

Step 6: Calculate the percent yield

% yield = actual yield / theoretical yield

% yield Na2CO3 = (2.92 grams / 3.18 grams) *100% =  91.8 %

% yield NaOH = (2.92 grams / 2.4 grams ) *100% = 121.6 %

% yield of Na2O = (2.92 grams / 1.86 grams ) * 100% = 157 %

The product made is Na2CO3, the other reactions have a % yield greater than 100 %

7 0
3 years ago
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