The answer would be A.Bias because the scientist can form a Bias opinion based on his beliefs
Answer:
21 g of N₂ are produced by the decomposition
Explanation:
The reaction is: 2 NaN3 → 2 Na + 3 N2
2 moles of sodium nitride decompose in order to produce 2 moles of Na and 3 moles of nitrogen gas.
According to stoichiometry, ratio is 2:3. Therefore we say,
2 moles of nitride can produce 3 moles of N₂
Then, 0.5 moles of NaN₃ will produce (0.5 . 3) / 2 = 0.75 moles of N₂
We convert the moles to mass, to find the answer
0.75 mol . 28 g / 1 mol = 21 g
<u>Answer:</u> The molality of the solution is 0.11 m
<u>Explanation:</u>
We are given:
Mole fraction of methanol = 0.135
This means that 0.135 moles of methanol is present in 1 mole of a solution
Moles of ethanol = 1 - 0.135 = 0.865 moles
To calculate the mass for given number of moles, we use the equation:
Moles of ethanol = 0.865 moles
Molar mass of ethanol = 46 g/mol
To calculate the molality of solution, we use the equation:
Where,
= Given mass of solute (methanol) = 0.135 g
= Molar mass of solute (methanol) = 32 g/mol
= Mass of solvent (ethanol) = 39.79 g
Putting values in above equation, we get:
Hence, the molality of the solution is 0.11 m
Answer:
CO is considered as a product.
Explanation:
A general chemical equation for a combination reaction follows:
To write a chemical equation, we must follow some of the rules:
The reactants must be written on the left side of the direction arrow.
A '+' sign is written between the reactants, when more than one reactants are present.
An arrow is added after all the reactants are written in the direction where reaction is taking place. Here, the reaction is taking place in forward direction.
The products must be written on the right side of the direction arrow.
A '+' sign is written between the products, when more than one products are present.
For the given chemical equation:
are the reactants in the reaction and are the products in the reaction.
Hence, CO is considered as a product.
Answer:
C-12 or C with a 12 superscripted on Upper left and 6 Subscripted on bottom left
Explanation:
Isotopic notation
