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Kruka [31]
3 years ago
13

Which of these organism do you think would have a niche similar to that of an African fish?

Chemistry
2 answers:
Art [367]3 years ago
5 0
B is the answer for sure
Kobotan [32]3 years ago
4 0

Answer:

B. the American bald eagle

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Help please please please please
Rom4ik [11]

Answer:

D. 18.7 grams

Explanation:

The coefficients are the key.

Create a proportion with them, and the molar mass, and then solve for x:

\frac{2}{3}  =  \frac{x}{28}  \\ 3x = 2(28) \\ 3x = 56 \\ x = 18.666... = 18.7

7 0
4 years ago
Which one of these situations would have higher density water? Water with a lower salt content Water at the equator Water near w
Nady [450]

Explanation:

water near where a river enters the ocean is having a higher density.

coz, ocean water has salt which increases water's density

6 0
3 years ago
Read 2 more answers
Balance the equation: "Sodium oxide reacts with water to form sodium hydroxide and hydrogen." I can't find the correct coefficie
dedylja [7]

Answer:

So, sodium oxide + water = sodium hydroxide + hydrogen is written Na2O+H2O-->NaOH+H.

To balance the equation it should read NaO+H2O-->2NaOH

Explanation:

Na2O+H2O-->2NaOH+0H2.......the 0H2 is dropped because there is no value

3 0
3 years ago
What is the frequency of a light that has a wavelength of 3.0 x 10 -7m?
alexdok [17]

Answer:

 frequency of light (f) = 1 x 10¹⁵s⁻¹

Explanation:

Given Data:

Wavelength of light λ = 3.0 x10⁻⁷m

Frequency of light: to be calculated

Formula Used to find frequency:

                                  f = V/λ ........................... (1)

where

f is the frequency

V is the velocity

λ is wavelength

Velocity of light = 3 x 10⁸ ms⁻¹

put the values in equation (1)

                                     f =  3 x 10⁸ ms⁻¹ / 3.0 x10⁻⁷m

                                     f = 1 x 10¹⁵s⁻¹

   So the frequency of light =  1 x 10¹⁵s⁻¹

7 0
3 years ago
what is the period of oscillation of an electron that is bouncing up and down in response to the passage of a packet of red lgih
Talja [164]

Answer:

2.33*10^-15 s

Explanation:

We need to estimate the period of oscillation of an electron that bounced up/down due to the effects of a passing packet of red light. The period of oscillation is the wavelength of the red light divided by the speed of the red light. We know that:

V = f*λ

where V = speed of the red light = 3*10^8 m/s

f = frequency = 1/T where T is the period of oscillation in seconds (s)

λ = the wavelength of the red light = 0.7*10^-6 m

Thus:

V = λ/T

T = λ/V = (0.7*10^-6)/(3*10^8) = 2.33*10^-15 s

7 0
3 years ago
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