Cu(s) + 2 AgNO3 = Cu(NO3)2 + 2 Ag 63.5 g Cu ---------------- 2 x 169.87 g AgNO3 ( mass Cu ?) -------------- 4.00 g AgNO3 mass Cu = 4.00 x 63.5 / 2 x 169.87 mass Cu = 254 / 339.74 = 0.747 g of Cu
Hope this helps
I would love to help but it is 3 or is it 3 million?
<span>Answer: 1.06 moles of molecules = 6.38x10²³ molecules
</span><span />
<span>Explanation:
</span><span />
<span>1) Balanced chemical equation:
</span><span />
<span>2Na + 2H₂O -> 2NaOH + H₂
</span><span />
<span>2) Mole ratios:
</span><span />
<span>2 mol Na : 2 mol H₂O : 2 mol NaOH : 1 mol H₂
</span><span />
<span>3) Convert 48.7 g of sodium to moles:
</span><span />
<span>number of moles = mass in grams / molar mass
</span><span />
<span>molar mass of Na = atomic mass = 23.0 g/mol
</span><span>number of moles = 48.7g / 23.0 g/mol = 2.12 moles of Na</span>
<span /><span>
4) Proportion:
</span><span />
<span>2moles Na/1mol H₂ = 2.12 moles Na / x
</span><span />
<span>x = 2.12 moles Na * 1 mol H₂ / 2 moles Na = 1.06 moles H₂.
</span><span />
<span>5) If you want to convert that to number of molecules you have to multiply by Avogadro's number: 6.022 x 10^²³
</span><span />
<span>1.06 mol x 6.022x10^²³ molecules/mol = 6.38x10²³ molecules</span>
Answer:
Density = 11.4 g/cm³
Explanation:
Given data:
Density of lead = ?
Height of lead bar = 0.500 cm
Width of lead bar = 1.55 cm
Length of lead bar = 25.00 cm
Mass of lead bar = 220.9 g
Solution:
Density = mass/ volume
Volume of bar = length × width × height
Volume of bar = 25.00 cm × 1.55 cm × 0.500 cm
Volume of bar = 19.4 cm³
Density of bar:
Density = 220.9 g/ 19.4 cm³
Density = 11.4 g/cm³
<u>Answer:</u>
<em>The mineral we are talking about here is olivine.</em>
<u>Explanation:</u>
It is a bit dark in color which ranges between yellow to Green to olive green. The luster present in it is nonmetallic luster but has a glassy finish and a substance hardness that is ranging between 6.5 to 7.
This mineral has granular masses which we can say has mass like sugar grains. This mineral has cleavage with conchoidal fracture present in it.