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salantis [7]
3 years ago
14

After two half-lives, a sample contains 10 grams of parent isotopes. How many grams of the parent isotope were present to start?

Chemistry
2 answers:
Lunna [17]3 years ago
8 0
T=2T
m=10 g

m=m₀2^(-t/T)

m₀=m/{2^(-2T/T)=m/2⁻²

m₀=10/2⁻²=40 g

40 grams
almond37 [142]3 years ago
8 0
Theirs a total of 39.9999G at the start
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Answer:

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When 2.00 g of methane are burned in a bomb calorimeter, the change in temperature is 3.08°C. The heat capacity of the calorimet
melisa1 [442]

Answer:

The approximate molar enthalpy of combustion of this substance is -66 kJ/mole.

Explanation:

First we have to calculate the heat gained by the calorimeter.

q=c\times \Delta T

where,

q = Heat gained = ?

c = Specific heat = 2.68 kJ/^oC

ΔT =  The change in temperature = 3.08°C

Now put all the given values in the above formula, we get:

q=2.68 kJ/^oC\times 3.08^oC

q=8.2544 kJ

Now we have to calculate molar enthalpy of combustion of this substance :

\Delta H_{comb}=-\frac{q}{n}

where,

\Delta H_{comb} = enthalpy change = ?

q = heat gained = 8.2544kJ

n = number of moles methane = \frac{\text{Mass of methane}}{\text{Molar mass of methane }}=\frac{2.00 g}{16.042 g/mol}=0.1247 mole

\Delta H_{comb}=-\frac{8.2544 kJ}{0.1247 mole}=-66.21 kJ/mole\approx -66 kJ/mole

Therefore,  the approximate molar enthalpy of combustion of this substance is -66 kJ/mole.

6 0
3 years ago
You throw a barbeque for your friends. Before you start the grill, your propane tank has a pressure of 78 psi. When you’re finis
Dvinal [7]

Answer:

b. 485 kPa

Explanation:

Gay-Lussac's law express that the pressure of a gas under constant volume is directly proportional to the absolute temperature. The equation is:

P1T2 = P2T1

<em>P is pressure and T absolute temperature of 1, initial state and 2, final state of the gas</em>

<em>Where P1 = 74psi</em>

<em>T2 = 20°C + 273.15 = 293.15K</em>

<em>P2 = ?</em>

<em>T1 = (95°F -32) * 5/9 + 273.15 = 308.15K</em>

<em />

Replacing:

74psi*293.15K = P2*308.15K

70.4psi

In kPa:

70.4psi * (6.895kPa / 1psi) =

<h3>b. 485 kPa </h3>

4 0
3 years ago
Properties of substances can be classified as physical or chemical properties. Which statements describe chemical properties? (C
Tamiku [17]

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Silver gets tarnished and becomes black when exposed to oxygen. This refers to a chemical change as silver a white and lustrous substance gets transformed into a tarnish black final substance. However, silver does not easily react with oxygen at usual circumstances. It easily reacts with sulfur comprising components in the air and generates black compound as Ag₂S.  

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horsena [70]

Answer:

b

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