The proton transfer reaction between Cyanide and water can be written as; X^- + H2O -----> HX + OH^-
<h3>What is a proton transfer reaction?</h3>
A proton transfer reaction is one in which a proton is moved from one chemical specie to another.It is in fact and acid - base reaction in the Brownstead - Lowry sense.
The proton transfer reaction between Cyanide and water can be written as(Let the cyanide ion be shown as X);
X^- + H2O -----> HX + OH^-
Learn more about proton transfer: brainly.com/question/861100?
Ok we can use boyle’s law (stating that P is proportional to V) to make the equation (P1V1) =(P2V2).
once we’ve done this, we can plug in the numbers:
(800•500) = (200•V2)
and then we get that
V2= 2000 ml
hope this helps!! :)
The balanced equation for reaction of solid cesium with liquid water
= 2Cs + 2H2O → 2CsOH + H2
cesium react with liquid water to produce cesium hydroxide and hydrogen gas
that is 2 moles of Cs react 2 moles of H2O to form 2 moles CsOH and 1 of hydrogen gas
Answer:
175 meters
Explanation:
As it's velocity is 35m/s
so,
by formula
35 *5
175 meters
