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Amiraneli [1.4K]
3 years ago
14

Which of these is found inside the solar system?

Chemistry
2 answers:
Trava [24]3 years ago
7 0

the answer would be B) Moon


Simora [160]3 years ago
7 0
<h3><u>Answer;</u></h3>

Moon

<h3><u>Explanation;</u></h3>
  • <em><u>Solar System consists of the stars, the Sun, and its orbiting planets, including the Earth, along with numerous moons, asteroids, comet material, rocks, and dust.</u></em>
  • The universe contains many galaxies and solar systems. A galaxy is a huge collection of gas, dust, and billions of stars and their solar systems.  A galaxy is held together by gravity. The galaxy that contains the Earth and its solar system is called the Milky Way.


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Zinc dissolves in hydrochloric acid to yield hydrogen gas: Zn(s) + 2HCl(aq) --&gt; ZnCl2(aq) + H2(g) When a 12.7 g chunk of zinc
ollegr [7]

Answer:

\boxed{\text{0.673 mol/L}}

Explanation:

We are given the amounts of two reactants, so this is a limiting reactant problem.

1. Data:

We know we will need an equation with masses and molar masses, so let’s gather all the information in one place.  

M_r:            65.38

                     Zn   +   2HCl ⟶ ZnCl₂ + H₂

m/g:             12.7

V/mL:                      5.00×10²

c/mol·L⁻¹:                  1.450

2. Moles of each reactant  

(a) Moles of Zn

n = \text{12.7 g Zn} \times \dfrac{\text{1 mol Zn}}{\text{65.38 g Zn}} = \text{0.1942 mol Zn}

(b) Moles of HCl

V = 5.0× 10² mL = 0.5000 L

n = \text{0.5000 L HCl}\times \dfrac{\text{1.450 mol HCl}}{\text{1 L HCl}} = \text{0.7250 mol HCl}

3. Identify the limiting reactant

Calculate the moles of ZnCl₂ obtained from each reactant

(i) From Zn

The molar ratio is 1 mol ZnCl₂:1 mol Zn

n = \text{0.1942 mol Zn} \times \dfrac{\text{1 mol ZnCl}_{2}}{\text{1 mol Zn}} = \text{0.1942 mol ZnCl}_{2}

(ii) From HCl

The molar ratio is 1 mol ZnCl₂:2 mol HCl

n = \text{0.7250 mol HCl} \times \dfrac{\text{1 mol ZnCl}_{2}}{\text{2 mol HCl}} = \text{0.3625 mol ZnCl}_{2}

Zinc is the limiting reactant, because it produces fewer moles of ZnCl₂.

4. Moles of HCl reacted

The molar ratio is 2 mol HCl:1 mol Zn

n = \text{0.1942 mol Zn} \times \dfrac{\text{2 mol HCl}}{\text{1 mol Zn}} = \boxed{\text{0.3885 mol HCl}}

5. Moles of HCl remaining

n = 0.7250 - 0.3885 = 0.3365 mol HCl

6. Concentration of hydrogen ions

The HCl is completely dissociated.

c = \dfrac{\text{0.3365 mol}}{\text{0.5000 L}} = \textbf{0.673 mol/L}\\\\\text{The concentration of hydrogen ions is $\boxed{\textbf{0.673 mol/L}}$}

4 0
3 years ago
El volumen de un gas en un recipiente cerrado es de 3.5 litros a una temperatura de 25oC y una atmósfera constante de presión. ¿
polet [3.4K]

Answer:

El volumen del gas en el recipiente es 3.29 L si se disminuye la temperatura a 7°C

Explanation:

La Ley de Charles es una ley de los gases que relaciona el volumen y la temperatura de una cierta cantidad de gas a presión constante.

Esta ley establece que el volumen es directamente proporcional a la temperatura del gas. Es decir que si la temperatura aumenta, el volumen del gas aumenta, mientras que si la temperatura del gas disminuye, el volumen disminuye.

Matemáticamente, si la cantidad de gas y la presión permanecen constantes, el cociente entre el volumen y la temperatura siempre tiene el mismo valor:

\frac{V}{T}=k

Suponiendo un cierto volumen de gas V1 que se encuentra a una temperatura T1 al comienzo del experimento, al variar el volumen de gas hasta un nuevo valor V2, entonces la temperatura cambiará a T2, y se cumplirá:

\frac{V1}{T1}=\frac{V2}{T2}

En este caso, sabes:

  • V1= 3.5 L
  • T1= 25 °C=298 °K (siendo 0°C=273°K)
  • V2=?
  • T2=7 °C=280 °K

Reemplazando:

\frac{3.5 L}{298 K}=\frac{V2}{280 K}

Y resolviendo obtienes:

V2=280 K*\frac{3.5 L}{298 K}

V2= 3.29 L

<u><em>El volumen del gas en el recipiente es 3.29 L si se disminuye la temperatura a 7°C</em></u>

5 0
2 years ago
152 dm^3 of gas has a pressure of 98.6 kpa. at what pressure will the volume be quartered
djverab [1.8K]

Answer:

P₂ = 394.4 KPa

Explanation:

Given data:

Volume of gas = 152 dm³

Pressure of gas = 98.6 KPa

Final pressure = ?

Final volume = quartered = 1/4×152 = 38 dm³

Solution:

P₁V₁ = P₂V₂

P₂ = P₁V₁/V₂

P₂ = 98.6 KPa .  152 dm³ / 38 dm³

P₂ = 14987.2 KPa.  dm³ / 38 dm³

P₂ = 394.4 KPa

6 0
3 years ago
Which unit can be used to express the rate of a reaction?
baherus [9]
It is moldm^-3s^-1
^ means raise to power

6 0
3 years ago
Which of the following is the smallest volume? 500 mL 2,500 cm3 5.5 x 10-1 L 25 m3
Anni [7]
500 ml is the answer
6 0
3 years ago
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