Answer:
3 miles and then 3 per mile for each additional mile
Length (2, 6) to (-4, 6) is sqrt((x2 - x1))^2 + (y2 - y1)^2) = sqrt((-4 -2)^2 + (6 - 6)^2) = sqrt((-6)^2 + 0) = 6
Length (2, 6) to (-4, 4) is sqrt((-4 - 2)^2 + (4 - 6)^2) = sqrt((-6)^2 + (-2)^2) = sqrt(36 + 4) = sqrt(40) = 2sqrt(10) units
Length (-4, 6) to (-4, 4) is sqrt((-4 - (-4))^2 + (4 - 6)^2) = sqrt(0^2 + (-2)^2) = 2
So the length of the longest side is 2sqrt(10) units
Answer:
[ - 2, - 7 ]
Step-by-step explanation:
A. Good luck with your exam
<span>46 <= grade < 96
First, let's write the equation for the lower limit that the student must get for a B.
(x + 92 + 82 + 88 + 92)/5 = 80
Multiply both sides by 5 giving
x + 92 + 82 + 88 + 92 = 400
Subtract 92, 82, 88, 92 from both sides
x = 400 - 92 - 82 - 88 - 92 = 46
So the student has to get 46 or higher on the test to make a B.
Now let's compute the upper limit
(x + 92 + 82 + 88 + 92)/5 < 90
Multiply both sides by 5
(x + 92 + 82 + 88 + 92) < 450
Subtract 92, 82, 88, 92 from both sides
x < 450 - 92 - 82 - 88 - 92 ) = 96
So the student has to get a grade of less than 96 to get a B.</span>