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patriot [66]
3 years ago
10

A student must have an average​ (the mean) on five tests that is greater than or equal to​ 80% but less than​ 90% to receive a f

inal grade of
b.​ devon's grades on the first four tests were​ 92%, 82%,​ 88%, and​ 92%. what range of grades on the fifth test would give him a b in the​ course?
Mathematics
1 answer:
Greeley [361]3 years ago
8 0
<span>46 <= grade < 96 First, let's write the equation for the lower limit that the student must get for a B. (x + 92 + 82 + 88 + 92)/5 = 80 Multiply both sides by 5 giving x + 92 + 82 + 88 + 92 = 400 Subtract 92, 82, 88, 92 from both sides x = 400 - 92 - 82 - 88 - 92 = 46 So the student has to get 46 or higher on the test to make a B. Now let's compute the upper limit (x + 92 + 82 + 88 + 92)/5 < 90 Multiply both sides by 5 (x + 92 + 82 + 88 + 92) < 450 Subtract 92, 82, 88, 92 from both sides x < 450 - 92 - 82 - 88 - 92 ) = 96 So the student has to get a grade of less than 96 to get a B.</span>
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the north pole is in the middle of the ocean. A person at sea level at the north pole would be 3,949 miles from the center of th
musickatia [10]

Answer:

7,897.30 miles

Step-by-step explanation:

It is given that the North Pole is at a distance of 3,949 miles from the center of the earth.

We also know that the sea floor is below 2.4 miles from the sea level.

It is given that a submarine is located at the sea floor near North Pole. Hence, the distance of the submarine from the center of the earth would be

3949 - 2.4 = 3946.6 miles.

On the other hand, the South Pole is given to be at an elevation of 1.7 miles from the sea level.

Since we know that the sea level is at a distance of 3949 miles from the center of the earth, we can immediately calculate the distance of the South Pole from the center of the earth to be

3949 + 1.7 = 3950.7 miles.

Putting all of this together, we see that the center of the earth is at a distance of 3946.6 miles from the submarine near the North Pole, and the center of the earth in turn is 3950.7 miles from the South Pole.

Hence, the distance between the submarine and a person on the South Pole = 3946.6 + 3950.7 = 7897.3 miles.

6 0
3 years ago
Solve for x 4(x+9)= 3(2x - 7)​
ElenaW [278]

Answer: X= 57/2

Hope this helps!

3 0
3 years ago
Read 2 more answers
Find the midpoint of points A(8,-7) and B(3,-1) graphically
sukhopar [10]

Answer: (5.5, -4)

Step-by-step explanation:

You can use the midpoint formula to find the midpoint of point A and point B.

M(\frac{x_{1}+x_{2} }{2}, \frac{y_{1} + y_{2} }{2})

x₁ = 8

x₂ = 3

y₁ = -7

y₂ = -1

M(\frac{x_{1}+x_{2} }{2}, \frac{y_{1} + y_{2} }{2})

M(\frac{8+3 }{2},  \frac{-7 +-1}{2} )

M(\frac{8+3 }{2},  \frac{-7 -1}{2} )

M(\frac{11 }{2},  \frac{-8}{2} )

M(5.5, -4 )

Midpoint = (5.5, -4)

Hope this helps!

3 0
3 years ago
A surveyor in a canyon takes measurements and draws the diagram shown.
Fiesta28 [93]

Answer:

\approx 118.4

Step-by-step explanation:

We know two sides and the angle between the sides, so we can use the Law of Cosines. Recall that the Law of Cosines states that:

c^2=a^2+b^2-2abcos(C), where a and b are the sides and C is the angle in between.

Let's substitute 115 for a, 178 for b, and 41 for Angle C.

Thus:

c^2=115^2+178^2-2(115)(178)cos(41)

c^2=44909-40940cos(41)

c=\sqrt{44909-40940cos(41)}

c \approx 118. 4

5 0
3 years ago
What is the measure of angle 3=
Nadya [2.5K]
180-42=138 angle 3=138
8 0
3 years ago
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