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4 years ago

Help me with my geometry homework, please

Mathematics

1 answer:

Ksju [112]4 years ago

4 0

Add 8x17 +the biggest number

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(0,3) (10,6) (40,15)

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3 years ago

Georgia adds two proper fractions and gets 8/7 as an answer Work out the two fractions.

LenaWriter [7]

Answer:

1/2 and 9/14

Step-by-step explanation:

Let the first fraction be 1/2

Let the second fraction be x

1/2 + x= 8/7

x= 8/7-1/3

= 16-7/14

= 9/14

Hence the two numbers are 1/2 and 9/14

4 0

3 years ago

Heya!

nataly862011 [7]

Answer:

$m\angle QSN=65^\circ$

Step-by-step explanation:

In the given figure, PQRS is a rhombus and SRM is an equilateral triangle.

We are also given that SN⊥RM and that ∠PRS = 55°.

And we want to find the measure of ∠QSN.

Remember that since PQRS is a rhombus, the angles formed by its diagonals are right angles. Let the intersection point of the diagonals be K. Therefore:

$m\angle RKS=90^\circ$

Now, RKS is also a triangle. The interior angles of all triangles must be 180. Thus:

$m\angle RKS+m\angle KSR+m\angle SRK=180$

Substitute in known values:

$90+55+m\angle KSR=180$

Solve for ∠KSR:

$m\angle KSR+145=180\Rightarrow m\angle KSR=35^\circ$

Since SRM is an equilateral triangle, this means that:

$m\angle SRM=m\angle RMS=m\angle MSR=60^\circ$

Note that RNS is also a triangle. Therefore:

$m\angle SRM+m\angle RNS+m\angle NSR=180$

Substitute in known values:

$60+90+m\angle NSR=180$

So:

$m\angle NSR+150=180\Rightarrow m\angle NSR=30^\circ$

∠QSN is the addition of the two angles:

$m\angle QSN=m\angle KSR+m\angle NSR$

Therefore:

$m\angle QSN=35+30=65^\circ$

4 0

3 years ago

Read 2 more answers

Complete the statement. 7- (-4) is units from 7 in the direction.

yawa3891 [41]

Answer:

- + - = -

7+4= -11

Step-by-step explanation:

Sorry if wrong

8 0

3 years ago

Read 2 more answers

A company is studying the number of monthly absences among its 125 employees. The following probability distribution shows the l

Angelina_Jolie [31]

Answer:

(1)

$E(x) = 0.72$

$Var(x) = 1.1616$

$\sigma = 1.078$

(2)

$E(x) = 12$

$Var(x) = 1.3$

$\sigma = 1.14$

Step-by-step explanation:

Solving (1):

$\begin{array}{ccccccc}{Days} & {0} & {1} & {2} & {3} & {4}& {5} \ \\ {Probability} & {0.60} & {0.20} & {0.12} & {0.04} & {0.04} & {0.00} \ \end{array}$